9 please. 3.4.5.6.7.8.9, 10, 11, 12, 13 and 14 Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint. 3. f(x, y)=x²-y²; x² + y² = 1 Answer + 4. f(x, y) = 3x + y; x² + y² = 10 5. f(x, y) = y; 4x² + y² = 8 Answer + 6. f(2,y)=ze*, tỷ 2 7. f(x, y, z)=2x+2y+z; 2² +²2² +2²=9 Answer 8. f(x, y, z)= ev; 2x² + y² + ² = 24 9. f(x, y, z) = xy² z; x² + y² + ² = 4 Answer + 10. f (x, y, z) = ln (2² + 1) + ln (y² + 1) + ln (2² + 1); x² + y² + ² = 12 11. f(x, y, z)=² +3 ¹+¹=1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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9 please.
3.4.5.6.7.8.9, 10, 11, 12, 13 and 14 Each of these extreme value
problems has a solution with both a maximum value and a minimum
value. Use Lagrange multipliers to find the extreme values of the function
subject to the given constraint.
3. f(x, y)=x²-y²; x² + y² = 1
Answer +
4. f(x, y) = 3x + y; x² + y² = 10
5. f(x, y) = y; 4x² + y² = 8
Answer +
6. f(x,y)=ze"; x² + y² = 2
7. f(x, y, z)=2x+2y+z; x² + y² +2²=9
Answer +
8. f(z, y, z)=e*; 2x² + y² + ² = 24
9. f(x, y, z) = xy' z; x² + y² + ² = 4
Answer +
10. f(x, y, z) = ln (2² + 1) + ln (y² + 1) + ln (2² + 1); x² + y² + 2² = 12
11. f(x, y, z)=²+3² +2²; 2ª +3² + z = 1
Transcribed Image Text:9 please. 3.4.5.6.7.8.9, 10, 11, 12, 13 and 14 Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint. 3. f(x, y)=x²-y²; x² + y² = 1 Answer + 4. f(x, y) = 3x + y; x² + y² = 10 5. f(x, y) = y; 4x² + y² = 8 Answer + 6. f(x,y)=ze"; x² + y² = 2 7. f(x, y, z)=2x+2y+z; x² + y² +2²=9 Answer + 8. f(z, y, z)=e*; 2x² + y² + ² = 24 9. f(x, y, z) = xy' z; x² + y² + ² = 4 Answer + 10. f(x, y, z) = ln (2² + 1) + ln (y² + 1) + ln (2² + 1); x² + y² + 2² = 12 11. f(x, y, z)=²+3² +2²; 2ª +3² + z = 1
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