Please use C++ language and only use the library <iostream>. Thank you! Perfect.cpp: deficient, abundant and perfect numbers#include using namespace std;const int LIMIT=5000;int sumofDivisors(int);int main(){int num, divisorSum;Declare three running totals andset them to zero here.for(num-1;num<=LIMIT; num++){divisorSum=sumofDivisors(num);if(divisorSum 9: perfect.cpp) A number is called perfect if the sum ofits divisors is equal to the original number. A number iscalled deficient if the sum of its divisors is less than theoriginal number. A number is called abundant if the sum ofits divisors is more than the original number. Write aprogram that answers the following questions: Whatnumbers below 5000 are perfect? What odd numbers below5000 are abundant? What are the relative proportions ofdeficient, abundant, and perfect numbers? 5000 should bein a global constant.

#include <iostream>using namespace std; const int LIMIT = 5000; int sumOfDivisors(int); int main() { int num, divisorSum; int cP = 0, cD = 0, cA = 0; for(num = 1; num <= LIMIT; num++) { divisorSum = sumOfDivisors(num); if(divisorSum == num) cP++; else if(divisorSum < num) cD++; else cA++; } cout << "What numbers below 5000 are perfect?" << endl; for(int i = 1; i <= LIMIT; i++) { if(sumOfDivisors(i) == i) cout << i << " "; } cout << "\n\n"; cout << "What odd numbers below 5000 are abundant?" << endl; for(int i = 1; i <= LIMIT; i += 2) { if(sumOfDivisors(i) > i) cout << i << " "; } cout << "\n\n"; cout << "Proportion of deficient, abundant, and perfect numbers = " << cD << " : " << cA << " : " << cP << endl; return 0;} int sumOfDivisors(int x) { int sum = 0; for(int i = 1; i <= (x/2); i++) { if(x % i == 0) sum += i; } return sum;}