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- Q11The joint probability function of two discrete random variables X and X is given by f(x, y) = cxy for x = 1, 2, 3 and y = 1, 2, 3, and equals zero otherwise. Find (a) the constant c, (b) PCX = 2, Y = 3), (c) P(1 ≤X ≤ 2, Y ≤ 2), (d) P(X22), (e) P(Y ). (c) P ¹). (c) P ( < X < ³), (d) P(Y < ¹), (e) whether X and Y are independent. dix dy C CXThe probability density function of a discrete random variable X is given by the following table: Px(X = 1) = .05 Px(X = 2) = .10 Px(X = 3) = .12 Px(X = 4) = .30 Px (X = 5) = .30 Px (X = 6) = .1i Px (X = 7) = .01 Px(X = 8) = .01 i) Compute E(X). ii) Compute Var(X). iii) Compute Px(X 3)
- b) The continuous random variable Y has the following probability density function. Pembolehubah rawak selanjar Y mempunyai fungsi ketumpatan kebarangkalian seperti berikut. Jh(3y² +2) ; -2sys2 0 ; otherwise f(y)={ 1 Show that h=- 24 i. 1 Tunjukkan bahawa h=; 24 ii. Based on the value in part (i), find the cumulative distribution function F(y). Berdasarkan nilai dalam bahagian (i), cari fungsi taburan longgokan F(y).Suppose an industry produced a particular type of metal mixture up to 1 ton a day. Due to technical difficulties or system breakdowns, the actual amount produced by the industry is Y, a random variable which has the following Probability density function: f(y) = √2y 0HelpZ is the present-value random variable for a whole life insurance of b payable at the moment of death of (x). You are given: (i) (ii) 8 = 0.05 (iii) The net single premium for this insurance is equal to Var(Z). Calculate b. x+t = 0.01 t≥0 (A) 1.36 (B) 1.68 (C) 2.00 (D) 2.32 (E) 2.645. Suppose that X is a discrete random variable with probability density function p(x) = cx², x = 1, 2, 3, 4. (c) Find Var(X). Select one: O a. 18.4 O b. 354 O c. none O d. 342.8H6.Let X be a random variable with the probability mass function (PMF) 0.05, =-2 0.25, г — 0 = 1 p(x) = 0.25, г — 2 %3| 0.35, x = 0.1, * = 5 otherwise 0, We can also summarize the key information of the above PME into a table; P(X = =) -2 0.05 0. 0.25 1. 0.25 0.35 0.1 What is the probability that X is non-negative and less than 2? O 0.5 O 0.1 O 0.25 O 0.85 2.Suppose X is a discrete random variable which only takes on positive integer values. For the cumulative distribution function associated to X the following values are known: F(23) 0.34 F(29) = =0.38 F(34) 0.42 F(39) 0.47 F(44) = 0.52 F(49) 0.55 F(56) = 0.61 = Determine Pr[29Recommended textbooks for youA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSONA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON