9) Here fct) - 2ltt 3) e 4) NOw, L{+s} = L{ th 3 2{} + 3 ト 3 =g(s) say So [:2e-5=constomt] - 2e-5 g(s+1) by frstolation theorem] - 2e-5) リルトマ +リや) 3 There fore the laplace tros form of 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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(4&5) can you explain in DETAIL how did you come up with this solution coz i'm going to make a script out of it
4)
Here fet) - 2ltt 3) e
(++5)
Now,
+ 3
3
= g(A) say
So
- 2e-5
g(s+1) by first tromlation theoremi]
3
There fore the laplace trons form of
J4) = 2 (4+3) e"(t+5) is 20 [y
5. Here Ht) = cos^t
Now, L{ft)) = L{cos"E}
1+ COs2t
A (A'+4)
lie.
Liteti}= 2(6*42)
There fore the laplace tromsform of
ft) = cos^t is
Transcribed Image Text:4) Here fet) - 2ltt 3) e (++5) Now, + 3 3 = g(A) say So - 2e-5 g(s+1) by first tromlation theoremi] 3 There fore the laplace trons form of J4) = 2 (4+3) e"(t+5) is 20 [y 5. Here Ht) = cos^t Now, L{ft)) = L{cos"E} 1+ COs2t A (A'+4) lie. Liteti}= 2(6*42) There fore the laplace tromsform of ft) = cos^t is
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