9) Here fct) - 2ltt 3) e 4) NOw, L{+s} = L{ th 3 2{} + 3 ト 3 =g(s) say So [:2e-5=constomt] - 2e-5 g(s+1) by frstolation theorem] - 2e-5) リルトマ +リや) 3 There fore the laplace tros form of 3
9) Here fct) - 2ltt 3) e 4) NOw, L{+s} = L{ th 3 2{} + 3 ト 3 =g(s) say So [:2e-5=constomt] - 2e-5 g(s+1) by frstolation theorem] - 2e-5) リルトマ +リや) 3 There fore the laplace tros form of 3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
(4&5) can you explain in DETAIL how did you come up with this solution coz i'm going to make a script out of it
![4)
Here fet) - 2ltt 3) e
(++5)
Now,
+ 3
3
= g(A) say
So
- 2e-5
g(s+1) by first tromlation theoremi]
3
There fore the laplace trons form of
J4) = 2 (4+3) e"(t+5) is 20 [y
5. Here Ht) = cos^t
Now, L{ft)) = L{cos"E}
1+ COs2t
A (A'+4)
lie.
Liteti}= 2(6*42)
There fore the laplace tromsform of
ft) = cos^t is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7aeab9f-45d2-48ed-b835-82ea42b1bf63%2Ff3adce99-3a3e-470d-b2f5-aff9209a1419%2Fgssfexe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4)
Here fet) - 2ltt 3) e
(++5)
Now,
+ 3
3
= g(A) say
So
- 2e-5
g(s+1) by first tromlation theoremi]
3
There fore the laplace trons form of
J4) = 2 (4+3) e"(t+5) is 20 [y
5. Here Ht) = cos^t
Now, L{ft)) = L{cos"E}
1+ COs2t
A (A'+4)
lie.
Liteti}= 2(6*42)
There fore the laplace tromsform of
ft) = cos^t is
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