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9 cos r+j9 sin 24 cos r+j24 sin + võ cos T+ jv6sin T+ V15 cos – j/15 sin T COS what would this be equivalent to?

9 cos r+j9 sin 24 cos r+j24 sin + võ cos T+ jv6sin T+ V15 cos – j/15 sin T COS what would this be equivalent to?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In simplifying the following 9 cos T+j9 sin T + v6 cos 끝ㅠ+jv6 sin 끊ㅠ+ V15 cos T-jV15sin승T 4 2 24 cos 자124 sin 3 what would this be equivalent to? The answer should be rounded-off to 4 decimal places. all of the choices O 0.3622 + j0.0971 – 2.3660 + j0.6340 + 0.6725 – j3.8141 Ocjs (5) - 2.3660 + j0.6430 + 0.6725 – j3.8141 12 9cjs(n +v6cjs (끝찌) + v15cjs (-m) 20 0.3622 – j0.0971 – 1.6935 – j3.1801
Transcribed Image Text:In simplifying the following 9 cos T+j9 sin T + v6 cos 끝ㅠ+jv6 sin 끊ㅠ+ V15 cos T-jV15sin승T 4 2 24 cos 자124 sin 3 what would this be equivalent to? The answer should be rounded-off to 4 decimal places. all of the choices O 0.3622 + j0.0971 – 2.3660 + j0.6340 + 0.6725 – j3.8141 Ocjs (5) - 2.3660 + j0.6430 + 0.6725 – j3.8141 12 9cjs(n +v6cjs (끝찌) + v15cjs (-m) 20 0.3622 – j0.0971 – 1.6935 – j3.1801
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