9 cos n+j9 sin 7 + 12 ⒤뀐⒤뀐⒤갓⒤갓뀐⒤빨⒤말⒤갓⒤갓⒤승ㅠ-jv15sin IT 24 cos 증짜124 sin 를" Round-off the answer to 4 decimal places.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Find the standard polar form of
3
3
9 cos
n+j9 sin
4
+ v6cos 끓ㅠ + jv6 sin 끓ㅠ+ v15 cos ㅠ - jv15 sin 승T
4
24 cos
-n+j24 sin
Round-off the answer to 4 decimal places.
O 3.3583 cjs (-1.9784)
O 4.7361 cjs (1.8557)
O 4.0827 cjs (–2.2857)
O 3.9692 cjs (–2.0388)
none of the choices
Transcribed Image Text:Find the standard polar form of 3 3 9 cos n+j9 sin 4 + v6cos 끓ㅠ + jv6 sin 끓ㅠ+ v15 cos ㅠ - jv15 sin 승T 4 24 cos -n+j24 sin Round-off the answer to 4 decimal places. O 3.3583 cjs (-1.9784) O 4.7361 cjs (1.8557) O 4.0827 cjs (–2.2857) O 3.9692 cjs (–2.0388) none of the choices
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