9: Consider an electric dipole where the positive charge, +q, is located on the positive z axis a distance d/2 above the x - y plane, and the negative charge, -q, is located on the negative z axis a distance d/2 below the xy plane, as shown. If the evaluation point is at a distance which is very large as compared to the separation between the charges, then the form of the expression for the net electric field has a very simplified form in terms of the electric dipole moment (EDM). k +91 d/2 -q Ε Part (a) Enter an exact expression for the magnitude of the vector Ẽ, the contribution of the positive charge to the electric field at the point (0, 0, z) where z> d/2. |E|=z (d/2) X Attempts Remain o Part (b) Enter an exact expression for the magnitude of the vector Ẽ, the contribution of the negative charge to the electric field at the point (0, 0, z) where z> d/2. result. Part (c) Enter an exact expression for the total electric field vector Ēnet, at the point (0, 0, 2). Part (d) Notice that when z »d, then z²±d²/4 z². Use this approximation to simplify your expression from the previous part. Enter your vector Part (e) The EDM (electric dipole moment) is represented by a vector, p. The magnitude of the vector is the product of the positive charge and the separation between the charges. The direction is from the negative and towards the positive charge. Rewrite your vector expression for the electric field of the dipole in terms of the EDM, p. Ē net view
9: Consider an electric dipole where the positive charge, +q, is located on the positive z axis a distance d/2 above the x - y plane, and the negative charge, -q, is located on the negative z axis a distance d/2 below the xy plane, as shown. If the evaluation point is at a distance which is very large as compared to the separation between the charges, then the form of the expression for the net electric field has a very simplified form in terms of the electric dipole moment (EDM). k +91 d/2 -q Ε Part (a) Enter an exact expression for the magnitude of the vector Ẽ, the contribution of the positive charge to the electric field at the point (0, 0, z) where z> d/2. |E|=z (d/2) X Attempts Remain o Part (b) Enter an exact expression for the magnitude of the vector Ẽ, the contribution of the negative charge to the electric field at the point (0, 0, z) where z> d/2. result. Part (c) Enter an exact expression for the total electric field vector Ēnet, at the point (0, 0, 2). Part (d) Notice that when z »d, then z²±d²/4 z². Use this approximation to simplify your expression from the previous part. Enter your vector Part (e) The EDM (electric dipole moment) is represented by a vector, p. The magnitude of the vector is the product of the positive charge and the separation between the charges. The direction is from the negative and towards the positive charge. Rewrite your vector expression for the electric field of the dipole in terms of the EDM, p. Ē net view
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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