9) A group of eight individuals with high cholesterol levels were given a new drug that was designed tolower cholesterol levels. Cholesterol levels, in milligrams per deciliter, were measured before and aftertreatment for each individual, with the following results:IndividualBefore12345678277287270273235255299277After216210170200173213185188NEE(a) Construct a 99.5% confidence interval for the mean reduction in cholesterol level. Let drepresent the difference in cholesterol level before and after treatment.10(b) A physician claims that the mean reduction in cholesterol level is more than 80 milligramsper deciliter. Does the confidence interval contradict this claim?

From the provided information, Sample size (n) = 8 Confidence level = 99.5%

Answered: 9) A group of eight individuals with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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.85%, 3.77 of 9 pts 7.1.19-T Question Help ▼ In a study of the accuracy of fast food drive-through orders, Restaurant A had 248 accurate orders and 56 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.171
Glaucoma is the leading cause of blindness in the United States. N. Ehlers measured the corneal thickness of nine patients who had glaucoma in one eye but not in the other. The following are the data on corneal thickness, in microns. Normal 484 478 492 444 430 398 464 404 476 Glaucoma 488 478 480 426 440 410 458 395 460 Construct and interpret a 95% confidence interval for the true mean difference in the mean corneal thickness in normal eyes and eyes with glaucoma. Include a filled out formula for your confidence interval and use the steps for a test hypothesis.
1. In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic processed tablet form. Cholesterol levels were measured before and after the treatment. The chang (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.2 and a standard devia 19.4. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in redu LDL cholesterol?
Three experiments investigating the relation between need for cognitive closure and persuasion were performed. Part of the study involved administering a "need for closure scale" to a group of students enrolled in an introductory psychology course. The "need for closure scale" has scores ranging from 101 to 201. For the 75 students in the highest quartile of the distribution, the mean score was x = 176.90. Assume a population standard deviation of ? = 7.71. These students were all classified as high on their need for closure. Assume that the 75 students represent a random sample of all students who are classified as high on their need for closure. Find a 95% confidence interval for the population mean score ? on the "need for closure scale" for all students with a high need for closure. (Round your answers to two decimal places.)
The average income of a large sample of households is $63,000 and the s.d. is $7,000. Assume that the data is approximately bell-shaped. What percent of these households have incomes between $42,000 and $77,000? Don’t forget to properly justify your answer using the empirical rule.
Heights (cm) of a random sample of students at a small Midwestern college: 183 154 170 189 187 176 193 150 181 187 162 175 157 159 185 164 189 173 166 179 157 177 169 159 188 191 163 183 177 180 1. Use these data for the following problems (input into a list and run the 1-VarStats). a. Find point estimates of u and o. b. Assume that o=12, construct a 95% confidence interval with the data and interpret in terms of the problem. C. (5) Find the margin of error m and the width of the confidence interval above.

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