**Problem 9-74: Determining the Center of Gravity of a Three-Wheeler****Objective:**Determine the location \((\bar{x}, \bar{y})\) of the center of gravity of the three-wheeler. The center of gravity for each component and its weight are tabulated in the figure. If the three-wheeler is symmetrical with respect to the \(x-y\) plane, determine the normal reaction each of its wheels exerts on the ground.**Components:**1. **Rear wheels:** 18 lb2. **Mechanical components:** 85 lb3. **Frame:** 120 lb4. **Front wheel:** 8 lb**Diagram Explanation:**The diagram shows a side view of a three-wheeler with labeled components and their respective weights. The following distances are given from a reference point \(A\):- The front wheel (Component 4) is 1 ft from \(A\).- Mechanical components (Component 2) are centered 1.5 ft from \(A\).- The frame (Component 3) is centered 2 ft from \(A\).- The rear wheels (Component 1) are centered 2.30 ft from \(A\).- \(A\) to base of rear wheels (Component 1) spans 1.40 ft.- \(A\) to back extends 0.80 ft.- The distance from \(A\) to \(B\) (the rear) is 2.30 ft.- The distance from \(B\) to another reference point (behind) is 1.30 ft.**Analysis:**To find the center of gravity \((\bar{x}, \bar{y})\), consider the distances from the reference point and the symmetrical nature of the vehicle in the \(x-y\) plane. Each component has specific coordinates and weights that should be used in the computation of \(\bar{x}\) and \(\bar{y}\).**Procedure:**1. Calculate the moment caused by each component about point \(A\).2. Sum the moments and divide by total weight to find the center of gravity.3. Use symmetry to confirm the position in the \(y\)-plane.4. Compute normal reactions at the wheels based on the derived center of gravity. *Note: Detailed steps for this calculation would typically involve setting up equations

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9-74. Determine the location (F, y) of the center of gravity of the three-wheeler. The location of the center of gravity of each component and its weight are tabulated in the figure. If the three-wheeler is symmetrical with respect to the x-y plane, determine the normal reaction each of its wheels ererts on th around

9-74. Determine the location (F, y) of the center of gravity of the three-wheeler. The location of the center of gravity of each component and its weight are tabulated in the figure. If the three-wheeler is symmetrical with respect to the x-y plane, determine the normal reaction each of its wheels ererts on th around

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

**Problem 9-74: Determining the Center of Gravity of a Three-Wheeler**

**Objective:**
Determine the location \((\bar{x}, \bar{y})\) of the center of gravity of the three-wheeler. The center of gravity for each component and its weight are tabulated in the figure. If the three-wheeler is symmetrical with respect to the \(x-y\) plane, determine the normal reaction each of its wheels exerts on the ground.

**Components:**
1. **Rear wheels:** 18 lb
2. **Mechanical components:** 85 lb
3. **Frame:** 120 lb
4. **Front wheel:** 8 lb

**Diagram Explanation:**
The diagram shows a side view of a three-wheeler with labeled components and their respective weights. The following distances are given from a reference point \(A\):

- The front wheel (Component 4) is 1 ft from \(A\).
- Mechanical components (Component 2) are centered 1.5 ft from \(A\).
- The frame (Component 3) is centered 2 ft from \(A\).
- The rear wheels (Component 1) are centered 2.30 ft from \(A\).
- \(A\) to base of rear wheels (Component 1) spans 1.40 ft.
- \(A\) to back extends 0.80 ft.
- The distance from \(A\) to \(B\) (the rear) is 2.30 ft.
- The distance from \(B\) to another reference point (behind) is 1.30 ft.

**Analysis:**
To find the center of gravity \((\bar{x}, \bar{y})\), consider the distances from the reference point and the symmetrical nature of the vehicle in the \(x-y\) plane. Each component has specific coordinates and weights that should be used in the computation of \(\bar{x}\) and \(\bar{y}\).

**Procedure:**
1. Calculate the moment caused by each component about point \(A\).
2. Sum the moments and divide by total weight to find the center of gravity.
3. Use symmetry to confirm the position in the \(y\)-plane.
4. Compute normal reactions at the wheels based on the derived center of gravity.

*Note: Detailed steps for this calculation would typically involve setting up equations

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