9 – 4x² -da | Evaluate: (A) f (x) = V9 – 4x² + 2 sin () +C B None of the given choices f (x) = /9 – 4x² + 2x sin¯' (5) - c. +C (D f (x) = 9 – 4x² – 2 sin (4) +C 9 – 4x² – 2x sin () -1 | E f (x) = %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
V9 – 4x2
-dx
Evaluate:
x²
-1
V9 – 4x2 + 2 sin (4)
+ C
f (x) =
B None of the given choices
f (x)
V9 – 4x2 + 2x sin (4)
+C
V9 – 4x2 – 2 sin ()
+ C
f (x) =
f (x) = -
V9 – 4x2 – 2x sin ()
+C
Transcribed Image Text:V9 – 4x2 -dx Evaluate: x² -1 V9 – 4x2 + 2 sin (4) + C f (x) = B None of the given choices f (x) V9 – 4x2 + 2x sin (4) +C V9 – 4x2 – 2 sin () + C f (x) = f (x) = - V9 – 4x2 – 2x sin () +C
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