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9-29. Given the data of Problem 9-11. Evaluate (a) the secondary compres- sion index and (b) the modified secondary compression index if e 2.60 Н, — 2.54 сm P, 2.75 Mg/m At i 0, е 1.74, Н — 1.928 сm At t = 1485 min, e = 1.455, Н 3D 1.728 ст Weight of technioion 1 otono ..11

9-29. Given the data of Problem 9-11. Evaluate (a) the secondary compres- sion index and (b) the modified secondary compression index if e 2.60 Н, — 2.54 сm P, 2.75 Mg/m At i 0, е 1.74, Н — 1.928 сm At t = 1485 min, e = 1.455, Н 3D 1.728 ст Weight of technioion 1 otono ..11

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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solve the problem 9-29 based on 11P. both are uploaded  in images.

9-29. Given the data of Problem 9-11. Evaluate (a) the secondary compres- sion index and (b) the modified secondary compression index if = 2.60 2.54 cm e o H. wwww = 2.75 Mg/m P, At i = 0, e = At i = 1.74, Н — 1.928 ст 3D 1.728 сm 1485 min, e = 1.455, H full 7 stone; moon phase Weight of technician
Transcribed Image Text:9-29. Given the data of Problem 9-11. Evaluate (a) the secondary compres- sion index and (b) the modified secondary compression index if = 2.60 2.54 cm e o H. wwww = 2.75 Mg/m P, At i = 0, e = At i = 1.74, Н — 1.928 ст 3D 1.728 сm 1485 min, e = 1.455, H full 7 stone; moon phase Weight of technician
11P: The time rate of settlement data shown below is for the increment from 20 to 40 kPa from the test in Fig. 8.5. The initial sample height is 2.54 cm, and there are porous stones on the top and at the bottom of the sample. Determine cv by (a) the log time-fitting procedure and (b) the square root of time procedure, (c) Compare the results of (a) and (b). Elapsed Time (min) Dial Reading (mm) 4.041 0.1 3.927 0.25 3.879 3.830 3.757 3.650 0.5 4 3.495 3.282 8 15 3.035 30 2.766 2.550 2.423 60 120 240 2.276 505 2.184 1485 2.040 12
Transcribed Image Text:11P: The time rate of settlement data shown below is for the increment from 20 to 40 kPa from the test in Fig. 8.5. The initial sample height is 2.54 cm, and there are porous stones on the top and at the bottom of the sample. Determine cv by (a) the log time-fitting procedure and (b) the square root of time procedure, (c) Compare the results of (a) and (b). Elapsed Time (min) Dial Reading (mm) 4.041 0.1 3.927 0.25 3.879 3.830 3.757 3.650 0.5 4 3.495 3.282 8 15 3.035 30 2.766 2.550 2.423 60 120 240 2.276 505 2.184 1485 2.040 12
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