Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![### Integrating Functions
#### Integrate the Given Function:
\[ \int \frac{\sqrt{9 - z^6}}{z^4} \, dz \]
Here is a step-by-step solution to integrate the given function:
1. Simplify the integrand if possible.
2. Determine an appropriate method of integration (e.g., substitution, integration by parts).
3. Perform the integration.
4. Add the constant of integration \( + C \) after integrating.
Use the provided space below to compute the integral:
```
[ __________ ]
+ C
```
Feel free to seek additional resources or consult a math textbook for guidance on solving integrals involving radicals and powers. Happy integrating!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F541bb107-0359-491e-bc63-cc05a5ca14fa%2F3530a02f-31ee-40be-baa9-25d97c060a9f%2Fhze45b_processed.png&w=3840&q=75)
Transcribed Image Text:### Integrating Functions
#### Integrate the Given Function:
\[ \int \frac{\sqrt{9 - z^6}}{z^4} \, dz \]
Here is a step-by-step solution to integrate the given function:
1. Simplify the integrand if possible.
2. Determine an appropriate method of integration (e.g., substitution, integration by parts).
3. Perform the integration.
4. Add the constant of integration \( + C \) after integrating.
Use the provided space below to compute the integral:
```
[ __________ ]
+ C
```
Feel free to seek additional resources or consult a math textbook for guidance on solving integrals involving radicals and powers. Happy integrating!
![**Indefinite Integral Calculation Guide**
**Problem Statement:**
Find the indefinite integral. You may omit absolute values from natural logarithms.
**Integral to Solve:**
\[ \int \frac{1}{(x+8)\sqrt{x^2 + 16x + 164}} \, dx \]
**Steps to Solve:**
1. **Simplify the Integrand:**
- Notice the quadratic expression under the square root.
- Complete the square for \(x^2 + 16x + 164\).
2. **Complete the Square:**
- The quadratic \(x^2 + 16x + 164\) can be rewritten as:
\[ x^2 + 16x + 64 + 100 = (x + 8)^2 + 100 \]
- Thus, the integral becomes:
\[ \int \frac{1}{(x+8)\sqrt{(x+8)^2 + 100}} \, dx \]
3. **Substitution:**
- Use \( u = x + 8\), hence \( du = dx \):
\[ \int \frac{1}{u \sqrt{u^2 + 100}} \, du \]
4. **Simplify Using Known Integrals:**
- Recognize that this is in the form for a standard integral result:
\[ \int \frac{1}{u \sqrt{u^2 + a^2}} \, du = \frac{1}{a} \ln\left| \frac{u}{a + \sqrt{u^2 + a^2}} \right| + C \]
- Where in this problem \( a = 10 \) (since \(100 = 10^2\)).
5. **Substitute and Simplify:**
- Substitute back \( u = x + 8 \):
\[ \int \frac{1}{(x+8)\sqrt{(x+8)^2 + 100}} \, dx = \frac{1}{10} \ln\left|\frac{x+8}{10 + \sqrt{(x+8)^2 + 100}} \right| + C \]
6. **Final Answer:**
- The final integral result is:
\[ \frac{1}{10} \ln\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F541bb107-0359-491e-bc63-cc05a5ca14fa%2F3530a02f-31ee-40be-baa9-25d97c060a9f%2Fbccqrzm_processed.png&w=3840&q=75)
Transcribed Image Text:**Indefinite Integral Calculation Guide**
**Problem Statement:**
Find the indefinite integral. You may omit absolute values from natural logarithms.
**Integral to Solve:**
\[ \int \frac{1}{(x+8)\sqrt{x^2 + 16x + 164}} \, dx \]
**Steps to Solve:**
1. **Simplify the Integrand:**
- Notice the quadratic expression under the square root.
- Complete the square for \(x^2 + 16x + 164\).
2. **Complete the Square:**
- The quadratic \(x^2 + 16x + 164\) can be rewritten as:
\[ x^2 + 16x + 64 + 100 = (x + 8)^2 + 100 \]
- Thus, the integral becomes:
\[ \int \frac{1}{(x+8)\sqrt{(x+8)^2 + 100}} \, dx \]
3. **Substitution:**
- Use \( u = x + 8\), hence \( du = dx \):
\[ \int \frac{1}{u \sqrt{u^2 + 100}} \, du \]
4. **Simplify Using Known Integrals:**
- Recognize that this is in the form for a standard integral result:
\[ \int \frac{1}{u \sqrt{u^2 + a^2}} \, du = \frac{1}{a} \ln\left| \frac{u}{a + \sqrt{u^2 + a^2}} \right| + C \]
- Where in this problem \( a = 10 \) (since \(100 = 10^2\)).
5. **Substitute and Simplify:**
- Substitute back \( u = x + 8 \):
\[ \int \frac{1}{(x+8)\sqrt{(x+8)^2 + 100}} \, dx = \frac{1}{10} \ln\left|\frac{x+8}{10 + \sqrt{(x+8)^2 + 100}} \right| + C \]
6. **Final Answer:**
- The final integral result is:
\[ \frac{1}{10} \ln\
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