9-18. A simply supported beam is subjected to a quadratic distributed load as shown in Fig. P9.18. y w(x) = - Wo x(x-21) Wo X. -1 Figure P9.18 Simply supported beam subjected to a quadratic distributed load. (a) Determine the total resultant force, 1. w(x) dx. %3D (b) Determine the x-location of the resultant R; in other words, deter- mine the centroid of the area under the distributed load | xw(x) dx sdrome R II 18

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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9-18. A simply supported beam is subjected
to a quadratic distributed load as shown
in Fig. P9.18.
y
Wo
w(x) = - x(x - 21)
WO
-1
Figure P9.18 Simply supported beam subjected to
a quadratic distributed load.
(a) Determine the total resultant force,
R = [
w(x) dx.
(b) Determine the x-location of the
resultant R; in other words, deter-
mine the centroid of the area under
the distributed load i
mou
x w(x) dx
x =
||
18
Transcribed Image Text:9-18. A simply supported beam is subjected to a quadratic distributed load as shown in Fig. P9.18. y Wo w(x) = - x(x - 21) WO -1 Figure P9.18 Simply supported beam subjected to a quadratic distributed load. (a) Determine the total resultant force, R = [ w(x) dx. (b) Determine the x-location of the resultant R; in other words, deter- mine the centroid of the area under the distributed load i mou x w(x) dx x = || 18
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