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9) 15m- +2lm + 6

9) 15m- +2lm + 6

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I'm supposed to be factoring but I don't get question 9, can you help me?

Here is a transcription of the text along with a detailed explanation. --- ### Algebraic Factoring Problems **Factor each completely:** 5) \( v^2 + 2v - 15 \) Factorization: \( (v - 3)(v + 5) \) 7) \( p^2 - 5p + 6 \) Factorization: \( (p - 2)(p - 3) \) 9) \( 15m^2 + 21m + 6 \) 11) \( 2n^2 + 11n + 12 \) 13) \( 4p^2 + 4p - 15 \) 15) \( 4b^2 - 5b + 1 \) ### Explanation The objective is to factor each quadratic expression completely. Factoring is the process of breaking down an expression into a product of simpler expressions, usually two binomials for quadratic expressions. For problems 5 and 7, the factors are provided. In each case, these factors are binomials that, when multiplied, yield the original expression. Problems 9, 11, 13, and 15 are presented for factorization practice without given solutions. The goal would be to find two binomials that multiply to give the original quadratic expression. When factoring, look for pairs of numbers that both add or subtract to give the middle coefficient (linear term) and multiply to give the constant term (last term). ---
Transcribed Image Text:Here is a transcription of the text along with a detailed explanation. --- ### Algebraic Factoring Problems **Factor each completely:** 5) \( v^2 + 2v - 15 \) Factorization: \( (v - 3)(v + 5) \) 7) \( p^2 - 5p + 6 \) Factorization: \( (p - 2)(p - 3) \) 9) \( 15m^2 + 21m + 6 \) 11) \( 2n^2 + 11n + 12 \) 13) \( 4p^2 + 4p - 15 \) 15) \( 4b^2 - 5b + 1 \) ### Explanation The objective is to factor each quadratic expression completely. Factoring is the process of breaking down an expression into a product of simpler expressions, usually two binomials for quadratic expressions. For problems 5 and 7, the factors are provided. In each case, these factors are binomials that, when multiplied, yield the original expression. Problems 9, 11, 13, and 15 are presented for factorization practice without given solutions. The goal would be to find two binomials that multiply to give the original quadratic expression. When factoring, look for pairs of numbers that both add or subtract to give the middle coefficient (linear term) and multiply to give the constant term (last term). ---
Expert Solution
Step 1

Given:-

15m2+21m+6

To find:-

Factor the given quadratic equation

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