8m L=6m f B 200 KN 2m N 2m BKN L=Sm Imm D 41.5m Use TME I= 1500 x 10 mm Det. a.) MA b.) MB c.) Rc d.) Mmax e.) So in mm
8m L=6m f B 200 KN 2m N 2m BKN L=Sm Imm D 41.5m Use TME I= 1500 x 10 mm Det. a.) MA b.) MB c.) Rc d.) Mmax e.) So in mm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:SIT. 2
8m
L=6m
A
B
200 KN 2m
2m1
вкнут
L=Sm
Imm
D
A 1.5m
с
Use TME
E = 2006 Pa
I= = 1500 x 10 mm ²
Det.
a.) MA
b.) MB
c.) Rc
d.) Mman
e.) So in mm
Expert Solution

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Step 1: Given
VIEWStep 2: Simplifying the given beam
VIEWSolution
VIEWStep 3: Span A'AB
VIEWStep 4: Span ABC
VIEWStep 5: Determination of 3 moment factor for partial uvl
VIEWStep 6: Final 3 moment equation for Span ABC
VIEWStep 7: Determination of support moments
VIEWStep 8: Free body diagram
VIEWStep 9: Deflection at D
VIEWStep 10: Deflection at D
VIEWStep by step
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