8)Given a receive power of 80E-6 mW and a noise power in decibels of [N]= -125DBW, determine the decibel SNR value. a. [SNR] = -80e-6 dBm – 123.5 dBm = -173.5 dB b. [SNR] = -40.97BM – (123.5 dBm) = -165.97 dB c. [SNR] = -40.97 dBm – (-95 dBm) = 54.03 dB d. [SNR] = 40.97 dBm – (-125 dBm) = +84.03 dB

8)Given a receive power of 80E-6 mW and a noise power in decibels of [N]= -125DBW, determine the decibel SNR value. a. [SNR] = -80e-6 dBm – 123.5 dBm = -173.5 dB b. [SNR] = -40.97BM – (123.5 dBm) = -165.97 dB c. [SNR] = -40.97 dBm – (-95 dBm) = 54.03 dB d. [SNR] = 40.97 dBm – (-125 dBm) = +84.03 dB

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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