*87. For any type of wave that reaches a boundary beyond which its speed is increased, there is a maximum incident angle if incident angle 0¡M corresponds to an angle of refraction equal to 90°. If 0; > Oim , all the wave is reflected at the boundary and none is refracted, because refraction would correspond to sin 0, > 1 (where 0, is the angle of refraction), which is impossible. This phenomenon is referred to as total internal reflection. (a) Find a formula for 0jM using the law of refraction, Eq. 11-20. (b) How far from the there is to be a transmitted refracted wave. This maximum bank should a trout fisherman Şound wave stand (Fig. 11–61) so trout won't be frightened by his voice (1.8 m above the ground)? The speed of sound is about 343 m/s in air and 1440 m/s in water. FIGURE 11-61 Problem 87b.
*87. For any type of wave that reaches a boundary beyond which its speed is increased, there is a maximum incident angle if incident angle 0¡M corresponds to an angle of refraction equal to 90°. If 0; > Oim , all the wave is reflected at the boundary and none is refracted, because refraction would correspond to sin 0, > 1 (where 0, is the angle of refraction), which is impossible. This phenomenon is referred to as total internal reflection. (a) Find a formula for 0jM using the law of refraction, Eq. 11-20. (b) How far from the there is to be a transmitted refracted wave. This maximum bank should a trout fisherman Şound wave stand (Fig. 11–61) so trout won't be frightened by his voice (1.8 m above the ground)? The speed of sound is about 343 m/s in air and 1440 m/s in water. FIGURE 11-61 Problem 87b.
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![*87. For any type of wave that reaches a boundary beyond which
its speed is increased, there is a maximum incident angle if
incident angle 0¡M corresponds to an angle of refraction
equal to 90°. If 0; > Oim , all the wave is reflected at the
boundary and none is refracted, because refraction would
correspond to sin 0, > 1 (where 0, is the angle of refraction),
which is impossible. This phenomenon is referred to as
total internal reflection. (a) Find a formula
for 0jM using the law of refraction,
Eq. 11-20. (b) How far from the
there is to be a transmitted refracted wave. This maximum
bank should a trout fisherman
Şound
wave
stand (Fig. 11–61) so trout
won't be frightened by his
voice (1.8 m above the
ground)? The speed
of sound is about
343 m/s in air and
1440 m/s in water.
FIGURE 11-61 Problem 87b.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c7939ec-14cc-4691-8556-ae479554bfec%2F07a417cb-ab0b-48d6-93c4-922a68d9c44d%2F8o836mq.png&w=3840&q=75)
Transcribed Image Text:*87. For any type of wave that reaches a boundary beyond which
its speed is increased, there is a maximum incident angle if
incident angle 0¡M corresponds to an angle of refraction
equal to 90°. If 0; > Oim , all the wave is reflected at the
boundary and none is refracted, because refraction would
correspond to sin 0, > 1 (where 0, is the angle of refraction),
which is impossible. This phenomenon is referred to as
total internal reflection. (a) Find a formula
for 0jM using the law of refraction,
Eq. 11-20. (b) How far from the
there is to be a transmitted refracted wave. This maximum
bank should a trout fisherman
Şound
wave
stand (Fig. 11–61) so trout
won't be frightened by his
voice (1.8 m above the
ground)? The speed
of sound is about
343 m/s in air and
1440 m/s in water.
FIGURE 11-61 Problem 87b.
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