-87 The matrix A= -2 0 4 2 8 2 0 6 has a single real eigenvalue X = 2 with algebraic multiplicity three. (a) Find a basis for the associated eigenspace. Basis = { }. (b) is the matrix A defective? DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity OB. A is not defective because the eigenvectors are linearly independent Oc. A is defective because it has only one eigenvalue OD. A is not defective because the eigenvalue has algebraic multiplicity three
-87 The matrix A= -2 0 4 2 8 2 0 6 has a single real eigenvalue X = 2 with algebraic multiplicity three. (a) Find a basis for the associated eigenspace. Basis = { }. (b) is the matrix A defective? DA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity OB. A is not defective because the eigenvectors are linearly independent Oc. A is defective because it has only one eigenvalue OD. A is not defective because the eigenvalue has algebraic multiplicity three
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Answer parts C and D please!
![-2 0-87
2
8
0 6
has a single real eigenvalue X = 2 with algebraic multiplicity three.
(a) Find a basis for the associated eigenspace.
The matrix 4 = 4
2
Basis = {}
(b) Is the matrix A defective?
OA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity
OB. A is not defective because the eigenvectors are linearly independent
Oc. A is defective because it has only one eigenvalue
OD. A is not defective because the eigenvalue has algebraic multiplicity three](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48ec5fd8-910b-4725-8318-e53781259bdf%2F770d21cc-0e1c-4805-83ae-4a52e10553f2%2F2qxqwcl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:-2 0-87
2
8
0 6
has a single real eigenvalue X = 2 with algebraic multiplicity three.
(a) Find a basis for the associated eigenspace.
The matrix 4 = 4
2
Basis = {}
(b) Is the matrix A defective?
OA. A is defective because the geometric multiplicity of the eigenvalue is less than the algebraic multiplicity
OB. A is not defective because the eigenvectors are linearly independent
Oc. A is defective because it has only one eigenvalue
OD. A is not defective because the eigenvalue has algebraic multiplicity three
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