Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Problem 82:**
There is exactly one polynomial with integer coefficients with zeros of 2, 4, and 6.
**Explanation:**
To find a polynomial with given zeros, we can use the fact that if a polynomial has zeros at \( x = a \), \( x = b \), and \( x = c \), then the polynomial can be expressed in the factored form:
\[
P(x) = k(x - a)(x - b)(x - c)
\]
where \( k \) is a nonzero constant.
For the zeros 2, 4, and 6, and since we want integer coefficients, we can set \( k = 1 \). Therefore, the polynomial is:
\[
P(x) = (x - 2)(x - 4)(x - 6)
\]
Expanding this, we get the polynomial:
\[
P(x) = (x - 2)(x^2 - 10x + 24) = x^3 - 10x^2 + 24x - 2x^2 + 20x - 48
\]
Simplifying, the polynomial with integer coefficients is:
\[
P(x) = x^3 - 12x^2 + 44x - 48
\]
Thus, the polynomial \( P(x) = x^3 - 12x^2 + 44x - 48 \) is the polynomial with integer coefficients that has zeros at 2, 4, and 6.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34aa3c00-4e68-4586-905d-c19fda080a0f%2Fe2425d42-e02d-443d-8eef-afd5b361e4d0%2Fi6vc3i5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 82:**
There is exactly one polynomial with integer coefficients with zeros of 2, 4, and 6.
**Explanation:**
To find a polynomial with given zeros, we can use the fact that if a polynomial has zeros at \( x = a \), \( x = b \), and \( x = c \), then the polynomial can be expressed in the factored form:
\[
P(x) = k(x - a)(x - b)(x - c)
\]
where \( k \) is a nonzero constant.
For the zeros 2, 4, and 6, and since we want integer coefficients, we can set \( k = 1 \). Therefore, the polynomial is:
\[
P(x) = (x - 2)(x - 4)(x - 6)
\]
Expanding this, we get the polynomial:
\[
P(x) = (x - 2)(x^2 - 10x + 24) = x^3 - 10x^2 + 24x - 2x^2 + 20x - 48
\]
Simplifying, the polynomial with integer coefficients is:
\[
P(x) = x^3 - 12x^2 + 44x - 48
\]
Thus, the polynomial \( P(x) = x^3 - 12x^2 + 44x - 48 \) is the polynomial with integer coefficients that has zeros at 2, 4, and 6.
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