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82. 80. 5 10 8 15 | 091 W 18 6 81. 83. 21 6 14 14 10 X i 8 r 8 inbey nop 80. W=_ 81. r= 82. t= 83. x= y =____

82. 80. 5 10 8 15 | 091 W 18 6 81. 83. 21 6 14 14 10 X i 8 r 8 inbey nop 80. W=_ 81. r= 82. t= 83. x= y =____

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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52 82. 80. t 5 10 Geometry Two shapes are similar if one shape can be flipped, rotated, or shrunk to exactly match the other. Similar shapes have sides that are proportional. This means that the ratios of the lengths of the corresponding sides are the same. EXAMPLE The rectangles below are similar. Find the missing side length. h 20 25 20 eno o 12 Stran 18 The ratio of the short side of the first rectangle to the short side of the second rectangle is h:12. The ratio of the long side of the first rectangle to the long side of the second rectangle is 25:20. miynon vor alle pa The rectangles are similar, so h:12= 25:20. This means Solving for h, we have h=15. 1/2=25 20 Find the missing side length(s) in each pair of similar shapes below. 81. 80. W = problem below. 21 aling hollenhouttigien 15 E to quong a asob bruog ynemorabis DO 81. r= 8 collid 14 W 40 83. bns 6 14 X sep oferto bebe y sop sabe poa 9 Heater PRACTICE 8 apre 18 6 10 r .8T 82. t= 83. x = y =___ Beast Academy Practice 5C
Transcribed Image Text:52 82. 80. t 5 10 Geometry Two shapes are similar if one shape can be flipped, rotated, or shrunk to exactly match the other. Similar shapes have sides that are proportional. This means that the ratios of the lengths of the corresponding sides are the same. EXAMPLE The rectangles below are similar. Find the missing side length. h 20 25 20 eno o 12 Stran 18 The ratio of the short side of the first rectangle to the short side of the second rectangle is h:12. The ratio of the long side of the first rectangle to the long side of the second rectangle is 25:20. miynon vor alle pa The rectangles are similar, so h:12= 25:20. This means Solving for h, we have h=15. 1/2=25 20 Find the missing side length(s) in each pair of similar shapes below. 81. 80. W = problem below. 21 aling hollenhouttigien 15 E to quong a asob bruog ynemorabis DO 81. r= 8 collid 14 W 40 83. bns 6 14 X sep oferto bebe y sop sabe poa 9 Heater PRACTICE 8 apre 18 6 10 r .8T 82. t= 83. x = y =___ Beast Academy Practice 5C
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