Answered: 81 A unity feedback closed loop second…

81 A unity feedback closed loop second order system has a transfer function- and is excited by a s+0.6s +9 step input of 1 unit. The steady state error of the output is

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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81
A unity feedback closed loop second order system has a transfer function-
and is excited by a
s+0.6s +9
step input of 1 unit. The steady state error of the output is

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Q\ Solve the following questions while giving the reason for each point 25. Each RC circuit in an op-amp (a) causes the gain to roll off at -6 dB/octave (b) causes the gain to roll off at-20 dB/decade (c) reduces the midrange gain by 3 dB (d) answers (a) and (b) 26. If a certain op-amp has a midrange open-loop gain of 200,000 and a unity-gain frequency of 5 MHz, the gain-bandwidth product is (a) 200,000 Hz (b) 5,000,000 Hz. (c) 1 x 1012 Hz (d) not determinable from the information 27. The bandwidth of an ac amplifier having a lower critical frequency of 1 kHz and an upper critical frequency of 10 kHz is (a) 1 kHz (b) 9 kHz (c) 10 kHz (d) 11 kHz 28. The bandwidth of a de amplifier having an upper critical frequency of 100 kHz is (a) 100 kHz (b) unknown (c) infinity (d) 0 kHz 29. When negative feedback is used, the gain-bandwidth product of an op-amp (a) increases (b) decreases (c) stays the same (d) fluctuates 30. If a certain op-amp has a closed-loop gain of 20 and an upper critical…
Ex. 453. G(s)=k(s+96)/(s(s+88)) is the FTF of a unity-feedback closed-loop system. Sketch the root locus with respect to k. Determine the number of asymptotes (N), number of root loci (M), the breakaway point (s=B) and the entry point (s=E). Answers: N,M,B, and E. ans:4
R, OV OUT + Complete the analysis showing that Vo/Vin = -Rf/Rin Let currents be defined as 1 equals the current flowing through Rin from left to right 12 equals the current flowing into the Opamp 13 equals the current flowing through the feedback resistor from left to right. Write the KCL equation in terms of 11, 12, and 13 at the inverting node of the Op-Amp. O There is no current flowing in the circuit O 12 = 11 + 13 O 11 = 12 + 13 11 + 12 = 13
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this question from electronics two course
solve 3 ,4,5 fast please i have to study it