8086 microprocessor I m doing This signed instruction in mov ax -0DfH Mov BL, 0BC imul BL First -0DFH equivalent to FF21 right When I multiply BL which is BC to AL part which is 21 I got 073C which loaded to ax okey but In emulator I got the correct answer as F73C so we are different so how does this F come in can you explain that just where does F come in ?
8086 microprocessor I m doing This signed instruction in mov ax -0DfH Mov BL, 0BC imul BL First -0DFH equivalent to FF21 right When I multiply BL which is BC to AL part which is 21 I got 073C which loaded to ax okey but In emulator I got the correct answer as F73C so we are different so how does this F come in can you explain that just where does F come in ?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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8086 microprocessor
I m doing This signed instruction in mov ax -0DfH
Mov BL, 0BC
imul BL
First -0DFH equivalent to FF21 right
When I multiply BL which is BC to AL part which is 21 I got 073C which loaded to ax okey but
In emulator I got the correct answer as F73C so we are different so how does this F come in can you explain that just where does F come in ?
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