8 Alkyl Halides (X = CI, Br or I) :CH3XAВEFAlcoholsOHHOHOCH3OHAABBCCDDЕЕFFGGKetones, Aldehydes and Epoxides: Assume "then H,0" is included if a protonation step is neededH.H.PhPhPhJKPQROther reagents21 SOCI2, pyridine22 TSCI, pyridine23 Mg, Et2024 MeMgBr, then H2025 EtMgBr, then H2026 PhMgBr, then H2027 PhCH2MgBr, then H201 H30* (dilute H2SO4)2 conc. H2S04, heat11 PCC in CH2CI212 Na2Cr207, H2SO4, H2O13 BH3•THF or 9-BBN, then H2O2, NaOH14 Hg(OAc)2, H20, then NABH415 03, then Zn, HCI or DMS16 МСРВА or CH;COҙH17 Br2, light3 NaOEt4 t-BUOK5 H2, Pt6 H2, Lindlar's catalyst7 Na, NH38 LAH or xs LAH, then H2018 HBr9 NaBH4, CH3ОН19 HBr, ROOR20 PBR3 From the reagent list, identify the reagent needed for each transformation below:OHReagent code:OH Reagent code:OHReagent code:A Moving to another question will save this response.

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Science

Chemistry

8

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Crystal Structures

Solids are present all around us. They have different properties and applications. Diamond and graphite are two well-known solids. Diamond is the hardest material in the world and is used in making jewelry. Graphite on the other hand is soft. The lead of your pencil is graphite. Why are they so different in appearance and properties despite the fact they are chemically the same? Both are allotropes of carbon. The answer lies in the structure, the way constituent particles are arranged in the solids.

Question

Alkyl Halides (X = CI, Br or I) :
CH3X
A
В
E
F
Alcohols
OH
HO
HO
CH3OH
AA
BB
CC
DD
ЕЕ
FF
GG
Ketones, Aldehydes and Epoxides: Assume "then H,0" is included if a protonation step is needed
H.
H.
Ph
Ph
Ph
J
K
P
Q
R
Other reagents
21 SOCI2, pyridine
22 TSCI, pyridine
23 Mg, Et20
24 MeMgBr, then H20
25 EtMgBr, then H20
26 PhMgBr, then H20
27 PhCH2MgBr, then H20
1 H30* (dilute H2SO4)
2 conc. H2S04, heat
11 PCC in CH2CI2
12 Na2Cr207, H2SO4, H2O
13 BH3•THF or 9-BBN, then H2O2, NaOH
14 Hg(OAc)2, H20, then NABH4
15 03, then Zn, HCI or DMS
16 МСРВА or CH;COҙH
17 Br2, light
3 NaOEt
4 t-BUOK
5 H2, Pt
6 H2, Lindlar's catalyst
7 Na, NH3
8 LAH or xs LAH, then H20
18 HBr
9 NaBH4, CH3ОН
19 HBr, ROOR
20 PBR3

From the reagent list, identify the reagent needed for each transformation below:
OH
Reagent code:
OH Reagent code:
OH
Reagent code:
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