8.4.3 (B)PLEASE ONLY DO PROBLEM B. PROBLEM A IS AN EXAMPLE HOW THE ANSWER SHOULD LOOK. Exercise 8.4.3: Composition of relations and arrow diagrams.O AbouThe arrow diagrams for relations A and B are shown below. Both relations have the domain {a, b, c, d}.bAbв(a) Draw the arrow diagram for Bo ASolution ad.BOA(b) Draw the arrow diagram for A o B.Feedba

From diagrams A and B we have A={(a,a),(a,c),(b,d)} and B={(a,a),(c,d),(d,a)} A⊙B={(x,y)|∋z such…

Answered: 8.4.3 (B) PLEASE ONLY DO PROBLEM B.…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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4.6.1: Recursive function: Writing the base case. Add an if branch to complete double_pennies()'s base case.Sample output with inputs: 1 10Number of pennies after 10 days: 1024 Note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message # Returns number of pennies if pennies are doubled num_days timesdef double_pennies(num_pennies, num_days):total_pennies = 0 ''' Your solution goes here ''' else:total_pennies = double_pennies((num_pennies * 2), (num_days - 1)) return total_pennies # Program computes pennies if you have 1 penny today,# 2 pennies after one day, 4 after two days, and so onstarting_pennies = int(input())user_days = int(input()) print('Number of pennies after', user_days, 'days: ', end="")print(double_pennies(starting_pennies, user_days))
5.16 LAB: Cryptographic Hashing Algorithms Encryption methods, such as the Caesar Cipher encryption, allow us to encrypt and decrypt text using a special key. Another method of encrypting text / passwords is called hashing. Hashing uses special algorithms to 'scramble' the text, which is tougher to be hacked. The hash function can take numbers, letters, and symbols as input, then the function applies one of the special algorithms to output the scrambled text. The longer the output string is, the harder to hack the hashed data. The difference between hashing and the Caesar Cipher encryption is that one cannot 'decrypt' a hashed data to its original text. Since a hashed data cannot be decrypted, a user must enter the original text, which will be hashed by the program. Then the program compares the hashed value with the hashed data stored previously for the original text. A salt is used, at times, to create a random sequence that is added to the original text before using the hashing…
Exercise 11.5 (a) A cut-edge of a graph G = (V, E) is an edge whose removal paritions the graph into two or more connected components (note that some of these components can be single vertex). Give a O(|V]+ E) time algorithm to find all the cut-edges of G. Give a clear description of your algorithm and the pseudocode and argue the running time bound. (Hint: Again this is a modification of the algorithm to find cut-vertices. What is the condition for an edge to be a cut-edge? Can it lie on a simple cycle of G?) %3D (b) Run your algorithm on the undirected graph given in Figure 2. Show the main steps and output the cut edges of the graph. 1 3 7 3 DFS Tree Figure 2

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8.4.3 (B) PLEASE ONLY DO PROBLEM B. PROBLEM A IS AN EXAMPLE HOW THE ANSWER SHOULD LOOK.