Pls answer 8.21 CHAP. 8]SIGNAL FLOW GRAPHS203=The signal flow graph is given in Fig. 8-70. We have P₁ = G₁G₂, P₂=G₂G₁3, P₁₁-G₂ H₂, A = 1 +G₂ H₂, A₁ A₂ = 1, and=P₁A₁ + P₂A₂_G₂(G₁ + G₂)1+ G₂H₂==RG₂1RG3-H₂Fig. 8-70Putting G, G₁G₂H₂, we obtain C/R=G₁G₂ and the system transfer function becomes open-loop.8.20.Determine the elements for a canonical feedback system for the system of Problem 8.10.From Problem 8.10, P₁ = G₁G₂G3, P₂ = G₁, A = 1 + G₂ H₁ − G₁G₂ H₁ + G₂G, H₂, A₁ = 1, and A₂ = A.From Equation (8.3) we have2GP,A,G,G₂G₁ + G₁ + G₂G₂ H₁ - G₁G₂G₁H₁ +G₂G₂G4H₂i-1and from Equation (8.4) we obtainA-1G₂H₁G₁G₂H₂ +G₂GH₂H =GG₁G₂G3 + G₁+G₂G4 H₁ - G₁G₂G4 H₁ + G₂G₂G₁ H₂Supplementary Problems8.21. Find C/R for Fig. 8-71, using Equation (8.2).G₂G₁G₁G₂RCFig. 8-718.22.Determine a set of canonical feedback system transfer functions for the preceding problem, usingEquations (8.3) and (8.4).+G₁H₂H₂

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Answered: 8.21. Find C/R for Fig. 8-71, using…

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8.21. Find C/R for Fig. 8-71, using Equation (8.2). G₁ G₁ R H₁ H₂ Fig. 8-71 G₁ G₂

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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Concept explainers

Nodal Analysis

In the analysis of any electric circuit, nodal analysis is the method of determining the potential difference or voltage between different nodes in an electric circuit. A node is a point where two or more branches connect each other. In the nodal analysis, the voltages are determined in the terms of branch currents. The nodal analysis is also known as the node voltage method or branch current method. The nodal analysis method is one of the several applications of Kirchhoff's Current Law (KCL).

Question

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Pls answer 8.21

CHAP. 8]
SIGNAL FLOW GRAPHS
203
=
The signal flow graph is given in Fig. 8-70. We have P₁ = G₁G₂, P₂=G₂G₁3, P₁₁-G₂ H₂, A = 1 +
G₂ H₂, A₁ A₂ = 1, and
=
P₁A₁ + P₂A₂_G₂(G₁ + G₂)
1+ G₂H₂
=
=
R
G₂
1
R
G3
-H₂
Fig. 8-70
Putting G, G₁G₂H₂, we obtain C/R=G₁G₂ and the system transfer function becomes open-loop.
8.20.
Determine the elements for a canonical feedback system for the system of Problem 8.10.
From Problem 8.10, P₁ = G₁G₂G3, P₂ = G₁, A = 1 + G₂ H₁ − G₁G₂ H₁ + G₂G, H₂, A₁ = 1, and A₂ = A.
From Equation (8.3) we have
2
GP,A,G,G₂G₁ + G₁ + G₂G₂ H₁ - G₁G₂G₁H₁ +G₂G₂G4H₂
i-1
and from Equation (8.4) we obtain
A-1
G₂H₁G₁G₂H₂ +G₂GH₂
H =
G
G₁G₂G3 + G₁+G₂G4 H₁ - G₁G₂G4 H₁ + G₂G₂G₁ H₂
Supplementary Problems
8.21. Find C/R for Fig. 8-71, using Equation (8.2).
G₂
G₁
G₁
G₂
R
C
Fig. 8-71
8.22.
Determine a set of canonical feedback system transfer functions for the preceding problem, using
Equations (8.3) and (8.4).
+
G₁
H₂
H₂

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