8.00 uF 6.00 uF 2.00 μF 9.00 V 8.00 uF Question: What is the electric potential energy stored in each capacitor in the circuit? Step 1: Reduce the circuit, documenting the intermediate steps, by combining capacitors, and fill in the following missing details below regarding properties of the equivalent capacitor: Ceg8/3 ✔✔✔UF AV = 9.00 V μC UE, total = ½ Qtotal²/C= P Step 2: Work backwards. Consider the intermediate circuit found during combination: a circuit featuring three 8-μF capacitors in series. Recall: capacitors in series carry the same-select-- ✓as Ceq μC ---select-- Qs = AVs = Qg/Cg = [ Check: AVS + AVg + AVg = 9.00 V ???? ---select-- Step 3: Continue work backwards, now considering the original circuit. Capacitors in parallel, such as the 6-μF and 2-μF capacitors, have the same ---select--- equivalent capacitance. Using this fact, find all properties of the 6-µF and 2-µF capacitors. AV6-AV₂- v Qs = μC Check: Q₂ + Qs = Q ???? --select- V Furthermore, the 8-μF capacitors will each carry the same ✓. Additionally, capacitors in a parallel combination have the same potential difference their Step 4: Once any two properties of a given capacitor in a circuit are known (C, AV, or Q), the electric potential energy U₂ stored in that capacitor can be determined. Solve for U₂ for each individual capacitor. Recall: U₂ = ½ Q²/C = ½ Q AV = ½ C (AV)² UE.8= Ib.

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Chapter1: Units, Trigonometry. And Vectors

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Question: What is the electric potential energy stored in each capacitor in the circuit?

Step 1: Reduce the circuit, documenting the intermediate steps, by combining capacitors, and fill in the following missing details below regarding properties of the equivalent capacitor:

Step 2: Work backwards. Consider the intermediate circuit found during combination: a circuit featuring three 8-µF capacitors in series. Recall: capacitors in series carry the same charge. Furthermore, the 8-µF capacitors will each carry the same charge as C_eq.

Step 3: Continue to work backwards, now considering the original circuit. Capacitors in parallel, such as the 6-µF and 2-µF capacitors.

Step 4: Once any two properties of a given capacitor in a circuit are known (C, ΔV, or Q), the electric potential energy U_E stored in that capacitor can be determined. Solve for U_E for each indivicual capacitor. Recall: U_E = ½ Q²/C = ½ Q ΔV = ½ C (ΔV)²

8.00 uF
6.00 uF
2.00 uF
9.00 V
8.00 uF
Question: What is the electric potential energy stored in each capacitor in the circuit?
Step 1: Reduce the circuit, documenting the intermediate steps, by combining capacitors, and fill in the following missing details below regarding properties of the equivalent capacitor:
Ceq 8/3
=
✓✓ HF
AV = 9.00 V
Qtotal =
μC
UE, total = 1/2 Qtotal²/Ceq =
Step 2: Work backwards. Consider the intermediate circuit found during combination: a circuit featuring three 8-µF capacitors in series. Recall: capacitors in series carry the same ---select---
-select-
as Ceq
μC
p
Q8 =
AV8 = Q8/CB =[
V
Check: AV8 + AV8 + AV8 = 9.00 V ???? ---select--- ✔ |
Step 3: Continue to work backwards, now considering the original circuit. Capacitors in parallel, such as the 6-µF and 2-μF capacitors, have the same ---select---
equivalent capacitance. Using this fact, find all properties of the 6-μF and 2-μF capacitors.
AV6 = AV₂ =
V
μC
26 =
μC
с
Check: Q₂ + Q6 = Q8 ???? ---select---
μJ
μJ
u]
✓. Furthermore, the 8-µF capacitors will each carry the same
V Additionally, capacitors in a parallel combination have the same potential difference as their
Step 4: Once any two properties of a given capacitor in a circuit are known (C, AV, or Q), the electric potential energy UE stored in that capacitor can be determined. Solve for UE for each individual capacitor. Recall: UE = 1/2 Q²/C = ½ Q AV = ½ C (AV)²
UE,8 =
UE,6 =
UE,2 =
Check: UE,8 + UE,2 + UE,6 + UE,8 = UE, total ???? ---select---

Expert Solution

Step 1

Given that:

The capacitance is

$C_{1} = 8 μ F C_{2} = 6 μ F C_{3} = 2 μ F C_{4} = 8 μ F$

The voltage is $V = 9 V$

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