8.. A Nielsen survey provided the estimate that the mean number of hours of television viewing per household is 7.25 hours per day assume that the Nielsen survey involved 200 households and that the sample standard deviation was 2.5 hours per day Ten years ago the population mean number of hours of television viewing per household was reported to be 6.70 hours . Letting u= the population mean number of hours of television viewing per household in , test the hypotheses H : µ< 6.70 and H : u> 6.70 . use a = 0.01 !

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 26PFA
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8. . A Nielsen survey provided the estimate that the mean number of hours of
television viewing per household is 7.25 hours per day assume that the Nielsen
survey involved 200 households and that the sample standard deviation was 2.5 hours
per day. Ten years ago the population mean number of hours of television viewing
per household was reported to be 6.70 hours . Letting u= the population mean
number of hours of television viewing per household in , test the hypotheses
H : us 6.70 and
H: u> 6.70. use a = 0.01 .
Transcribed Image Text:8. . A Nielsen survey provided the estimate that the mean number of hours of television viewing per household is 7.25 hours per day assume that the Nielsen survey involved 200 households and that the sample standard deviation was 2.5 hours per day. Ten years ago the population mean number of hours of television viewing per household was reported to be 6.70 hours . Letting u= the population mean number of hours of television viewing per household in , test the hypotheses H : us 6.70 and H: u> 6.70. use a = 0.01 .
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