8. (x² + 2xy − 4y²) dx — (x² − 8xy — 4y²) dy = 0. - -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please answer number 8
1. (x − 2y) dx + (2x + y) dy = 0.
2. 2(2x² + y²) dx - xy dy = 0.
3. xy dx (x² + 3y²) dy = 0.
4. x²y' = 4x² + 7xy + 2y².
5. 3xy dx + (x² + y²) dy = 0.
6. (x − y)(4x + y)dx + x(5x − y) dy = 0.
i 7. (5v – u) du + (3v − 7u) dv = 0.
-
ANS. In (x² + y²) + 4 arc tan (y/x) = c.
ANS. x = c²(4x² + y²).
ANS. x² = 6y² ln \y/c|.
x²(y + 2x) = c(y + x).
8. (x² + 2xy − 4y²) dx — (x² – 8xy — 4y²) dy = 0.
-
9. (x² + y²) dx − xy dy = 0.
ANS.
ANS. x(y + x)² = c(y ¹³/2x).
ANS. (3v + u)² = c(v – u).
ANS. x² + 4y² = c(x + y).
ANS.. y² 2x² In \x/c\.
=
Transcribed Image Text:1. (x − 2y) dx + (2x + y) dy = 0. 2. 2(2x² + y²) dx - xy dy = 0. 3. xy dx (x² + 3y²) dy = 0. 4. x²y' = 4x² + 7xy + 2y². 5. 3xy dx + (x² + y²) dy = 0. 6. (x − y)(4x + y)dx + x(5x − y) dy = 0. i 7. (5v – u) du + (3v − 7u) dv = 0. - ANS. In (x² + y²) + 4 arc tan (y/x) = c. ANS. x = c²(4x² + y²). ANS. x² = 6y² ln \y/c|. x²(y + 2x) = c(y + x). 8. (x² + 2xy − 4y²) dx — (x² – 8xy — 4y²) dy = 0. - 9. (x² + y²) dx − xy dy = 0. ANS. ANS. x(y + x)² = c(y ¹³/2x). ANS. (3v + u)² = c(v – u). ANS. x² + 4y² = c(x + y). ANS.. y² 2x² In \x/c\. =
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