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- Given the following probability distribution for the number of semesters of Math a (non-Math major) college student will take as they earn their degree: x:number of semesters of Math 1 2 3 4 P(x) 0.25 0.45 0.20 0.10 What is the probability that a randomly selected (non-Math major) college student will have taken exactly 3 semesters of Math? Show how you calculated your result here (type in what you typed on your calculator or computer, etc) Calculation: __________ Now type in your final simplified or rounded answer, if necessary round your answer to four decimal places. P(exactly 3 semesters of Math) = _____________i need the answer quicklyThe average weekly income of a supervisor on duty in the glass industry has a normal distribution, with a mean of $ 1,000 and a standard deviation of $ 100. That is, μ = $ 1,000 and σ = $ 100. What is the probability to select a supervisor whose weekly income ranges from $ 1,000 to $ 1,100? This question is expressed with Probability notation as follows: P ($ 1,000 <weekly income <$ 1,100).
- Given the probability distributions shown to the right, complete the following parts. Distribution A Distribution B a. Compute the expected value for each distribution. b. Compute the standard deviation for each distribution. c. What is the probability that x will be at least 3 in Distribution A and Distribution B? d. Compare the results of distributions A and B. P(X = x,) P(X = x;) 0.46 0.03 0.25 1 0.12 0.14 2 0.14 2. 0.12 3 0.25 4. 0.03 4. 0.46 (Type an integer or decimal rounded to three decimal places as needed.) b. What is the standard deviation for distribution A? (Type an integer or decimal rounded to three decimal places as needed.) What is the standard deviation for distribution B? (Type an integer or decimal rounded to three decimal places as needed. c. What is the probability that x will be at least 3 in Distribution A? Next View instructor tip Help me solve this Get more help - 936 PM 70°F NO 21 P Type here to search 37/2022 CON & %23 2. R T. Y E tab 57 K S F. G D Cans lock…Suppose the probability distribution of x, the number of defective tires on a randomly selected car checked at a certain inspection station, is given in the following table. 이 p(x) 0.60 0.14 0.05 0.03 0.18 X 0 1 (a) Calculate the mean value of x. 2 3 4 (b) What is the probability that x exceeds its mean value?DII Given below are the sample means for fifteen samples consisting of five data values each. Assume that the mean of the sample means is ten and the computed values for the UCL and LCL of the chart are 15 and 5, respectively. Below is the chart. Is this process in statistical control? Why or why not? Select the best answer choice. Sample 1 2 3 Mean 9 11 6 17+ 16- 15 14+ 13+ 12+ 11+ 10- 9. 8+ 7- 6 5 4. 3- 2- 1- R Submit Question $ F4 % -1 + O No, because there are eight consecutive points all above or all below the centerline. O No, because there is a point lying beyond the upper or lower control limit. O No, because there is a pattern, trend, or cycle that is obviously not random. O No, because more than one of the answer choices above are correct. O Yes, this process is within statistical control. 5 T 4 5 12 9 ▬▬ FS 6 7 8 11 7 8 6 6 Y H 49 9 10 12 16 F6 8 & 7 9 U 11 12 6 13 J 10 F7 11 13 14 15 12 11 7 8 12 PrtScn 13 FB K 15 9 UCL centerline LCL Home 16 Q F9 L ) End 0 F10 A PgUp ☎
- I need help with C and DGiven the probability distributions shown to the right, complete the following parts. a. Compute the expected value for each distribution. b. Compute the standard deviation for each distribution. c. What is the probability that x will be at least 3 in Distribution A and Distribution B? d. Compare the results of distributions A and B. Distribution A Distribution B xi P(X=xi) xi P(X=xi) 0 0.03 0 0.46 1 0.11 1 0.23 2 0.17 2 0.17 3 0.23 3 0.11 4 0.46 4 0.03 Question content area bottom Part 1 a. What is the expected value for distribution A? μ=enter your response here (Type an integer or decimal rounded to three decimal places as needed.) Part 2 What is the expected value for distribution B? μ=enter your response here (Type an integer or decimal rounded to three decimal places as needed.) Part 3…Use the following information to answer A-C. The table below shows the probablity of a certain number of students having fatigue. (Out of 4 randomly selected students)/ x P(x) 0 0.10 1 0.20 2 0.35 3 0.30 4 0.05 A) What is the probability that more than 2 of 4 randomly selected students have fatigue? B) What is the mean (to the nearest 0.1) number of students with fatigue out of 4 randomly selected students? C) What is the standard deviation (to the nearest 0.1) of the number of students with fatigue out of 4 randomly selected students? [Show all work with a table or formula]
- Nicole has purchased the life insurance policy for her fish for the price of $200 per year and Nicole will receive $4000 in case if her fish passes away. The insurance company estimated the probability of her fish passing away during the length of the policy to be 0.5%. Let XX be the insurance company's profit. Answer the following questions: 1. Create the probability distribution table for XX : XX outcome profit xx ,$ P(X=x)P(X=x) fish passes away fish survives 2. Use the probability distribution table to find the following: E[X]=μX=E[X]=μX= dollars. (Round the answer to 1 decimal place.) SD[X]=σX=SD[X]=σX= dollars. (Round the answer to 1 decimal place.)i need the answer quicklyA survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.