Discrete Probability Distribution 8. There is a 50-50 chance that the queen carries the gene of hemophilia. If she is a carrier, theneach prince has a 50-50 chance of having hemophilia independently. If the queen is not acarrier, the prince will not have the disease. Suppose the queen has had three princes withoutthe disease. What is the probability the queen is a carrier?9. A certain area of the eastern United States is, on average, hit by 6 hurricanes a year. Find theprobability that in a given year that area will be hit by(a) fewer than 4 hurricanes.(b) anywhere from 6 to 8 hurricanes.

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Answered: 8. There is a 50-50 chance that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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N (people) Incidence rate (per 1,000 person-years) Group Person-time Events <6 hours/day 6-8 hours/day 8-9 hours/day 9-10 hours/day 10+ hours/day (person-years) 76,500 345,000 228,000 110,000 55,000 11,108 50,041 719 9.4 2,691 1,915 1,144 7.8 31,003 16,316 8,164 8.4 10.4 814 14.8 7. Compute relative comparisons between each of the different sleep groups, using the 6 to 8 hours per day group as the reference (or unexposed group). Group Incidence rate (per Relative rate ratio 1,000 person-years) <6 hours/day 6-8 hours/day 8-9 hours/day 9-10 hours/day 10+ hours/day 7.8 Reference
O RANDOM VARIABLES AND DISTRIBUTIONS Shasia Discrete probability distribution: Basic Fill in the P(x=x) values to give a legitimate probability distribution for the discrete random variable x, whose possible values are -1,3, 4, 5, and 6. Value x of X P(x = x) 1 0.10 圖 3 4 0.14 0.30 Explanation Check 2UZI MCUraw HlLEGUcation. All Rights Reser/ed. Terms of Use I Privacy Accessibility
The probability distribution of number of televisions per household in a small town 1 2 3 4 P(x) 0.03 0.11 0.33 0.43 0.10 (a) Find the probability of randomly selecting a household that has one or two televisions.
Distribution of first digits (Benford's Law) Digit 1 2 3 4 5 Probability 0.301 0.176 0.125 0.097 0.079 Digit 6 7 8 9 Probability 0.067 0.058 0.051 0.046 First digits in allegedly fraudulent checks First digit 1 2 3 4 5 6 7 8 9 Frequency 36 25 28 20 23 17 15 17 77 The first significant digit in any number must be 1, 2, 3, 4, 5, 6, 7, 8, or 9. It was discovered that first digits do not occur with equal frequency. Probabilities of occurrence to the first digit in a number are shown in the accompanying table. The probability distribution is now known as Benford's Law. For example, the following distribution represents the first digits in 188 allegedly fraudulent checks written to a bogus company by an employee attempting to embezzle funds from his employer. a) What is the test statistics? b) What is the p-value?
Conditional probability distribution Y given that X = 0.5 y f (x, y) -1.0 -2 1/3 -0.5 -1 1/6 0.5 1 1/6 1.0 2 1/3 fxv (0.5, y) fyix(y) = fx(0.5)
CONTINUOUS PROBABILITY
Fruit Fly Lifetimes Suppose that the probability function in the table below reflects the possible lifetimes (in months after emergence) for fruit flies. Let the random variable X measure fruit fly lifetimes (in months). Fruit fly lifetimes (in months) 1 2 3 4 5 6 p(x) | 0.30 ? 0.20 0.1o 0.10 0.05 (a) What proportion of fruit flies die in their second month? Enter the exact answer. P(X = 2) = i eTextbook and Media (b) What is the probability that a fruit fly lives more than four months? Enter the exact answer. P(more than four months) = eTextbook and Media (c) What is the mean lifetime for a fruit fly? Enter the exact answer. i months eTextbook and Media (d) What is the standard deviation of fruit fly lifetimes? Round your answer to two decimal places, O = i months eTextbook and Media
Actuarial Mathematicsss
ment i P(B) P(BC) Total Itranscript Complete the following probability table. (Round Prior Probability and Posterior Probability answers to 2 decimal places and Joint Probability answers to 4 decimal places.) Prior Probability Conditional Probability 0.52 P(AB) P(ABC) 0.52 Saved Prev 0.13 P(ANB) 0.47 P(ANB) P(A) A Joint Probability 1 of 12 Next > C Posterior Probability P(BIA) P(BCA) Total E Help Save 0.00 yo
If you have a data set of n items, the data are continuous variables, the data set is unimodal, and the data set is too skewed to use the normal distribution, which probability distribution should you use to calculate probabilities? Discrete uniform distribution Binomial distribution Poisson distribution Hypergeometric distribution Geometric distribution Uniform continuous distribution Standard normal distribution Exponential distribution Triangular distribution None of the above
5 A is the test a right tail left tail or two tail

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