8. Since the factors of (7-2)! can be rearranged in the following manner (7-2)!= it is easily verified that (7-2)! when divided by 7 gives a remainder of 1. In a similar manner, rearrange the factors of (11-2)! to show that the remainder is 1 when 9! is divided by 11. Deduce the remainder when 10! + 1 is divided by 11. 15 8 5.4.3.2.1=(5-3) (4-2)-1 =(7(2) + 1)(7(1) + 1)(7(0) + 1), [4]

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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8. Since the factors of (7-2)! can be rearranged in the following manner
(7-2)!=
15
8
5.4.3.2.1=(5-3) (4-2)-1 =(7(2) + 1)(7(1) + 1)(7(0) + 1),
[4]
it is easily verified that (7-2)! when divided by 7 gives a remainder of 1. In a similar manner, rearrange
the factors of (11-2)! to show that the remainder is 1 when 9! is divided by 11. Deduce the remainder
when 10! + 1 is divided by 11.
Transcribed Image Text:8. Since the factors of (7-2)! can be rearranged in the following manner (7-2)!= 15 8 5.4.3.2.1=(5-3) (4-2)-1 =(7(2) + 1)(7(1) + 1)(7(0) + 1), [4] it is easily verified that (7-2)! when divided by 7 gives a remainder of 1. In a similar manner, rearrange the factors of (11-2)! to show that the remainder is 1 when 9! is divided by 11. Deduce the remainder when 10! + 1 is divided by 11.
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