8. Point U is the midpoint of 2V. Find the value of x. Round to the nearest tenth if necessary. 6. 2х -11 T U Ox = 6 O x = -2.5 O x = 8.5 O x = 15

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Geometry Sem1 > Activity 1.4.1 - Segment Addition Postulate**

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## 8. Point \( U \) is the midpoint of \( \overline{TV} \). Find the value of \( x \). Round to the nearest tenth if necessary.

**Diagram Explanation:**
There is a horizontal line segment \( \overline{TV} \) with points \( T \), \( U \), and \( V \) marked on it. Point \( U \) is the midpoint of the segment \( \overline{TV} \).

- \( TU \) is labeled as \( 6 \).
- \( UV \) is labeled as \( 2x - 11 \).

The equation to find the value of \( x \):
Since \( U \) is the midpoint, \( TU = UV \).

Therefore, we can set up the equation:
\[ 6 = 2x - 11 \]

Now, solve for \( x \):
\[ 6 + 11 = 2x \]
\[ 17 = 2x \]
\[ x = \frac{17}{2} \]
\[ x = 8.5 \]

**Answer Choices:**
- \( x = 6 \)
- \( x = -2.5 \)
- \( x = 8.5 \) (Correct Answer)
- \( x = 15 \)
Transcribed Image Text:**Geometry Sem1 > Activity 1.4.1 - Segment Addition Postulate** --- ## 8. Point \( U \) is the midpoint of \( \overline{TV} \). Find the value of \( x \). Round to the nearest tenth if necessary. **Diagram Explanation:** There is a horizontal line segment \( \overline{TV} \) with points \( T \), \( U \), and \( V \) marked on it. Point \( U \) is the midpoint of the segment \( \overline{TV} \). - \( TU \) is labeled as \( 6 \). - \( UV \) is labeled as \( 2x - 11 \). The equation to find the value of \( x \): Since \( U \) is the midpoint, \( TU = UV \). Therefore, we can set up the equation: \[ 6 = 2x - 11 \] Now, solve for \( x \): \[ 6 + 11 = 2x \] \[ 17 = 2x \] \[ x = \frac{17}{2} \] \[ x = 8.5 \] **Answer Choices:** - \( x = 6 \) - \( x = -2.5 \) - \( x = 8.5 \) (Correct Answer) - \( x = 15 \)
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