8. List the truth table of the function: 9. Given the Boolean function: F=x'y+xy'+y'z F=xy+x'y'+y'z (a) implement it with AND, OR, and inverter gates, and (b) implement it with NAND gates only.
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- Simplify the following Boolean Function using K-map: F(a, b, c) = E(0,1,5,6,7) and implement the above function (a) With logic gates (AND, OR, Inverters) (b) With NAND gates (c) With NOR gatesThe previous solution was not clear, and there was ambiguity in the abbreviations. I need the correct and clear solution, please, from an expert in handwriting3. Discussion: 1. Convert the gray code 01011001 to decimal number and show your work. 2. Convert the gray code 00101101 to binary number and show your work. 3. Design a 8-bit binary to gray code conversion circuit using logic gates and verify your design. 4. Design a 8-bit gray to binary code conversion circuit using logic gates and verify your design.
- 5) below is the accuracy table showing the output values for two separate binary number entries (W and Y) with a length of two bits. Get the simplest form of output functions with the Karnaugh diagram. Draw a logic diagram of the circuit that performs the function of these functions.Describe in detail which functions a, b and C perform for 2-bit binary numbers in the input.T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseDesign a circuit called half adder (HA) which adds two 1-bit numbers, a,b and produces 2-bit output, c. a. Draw the truth table of the circuit.b. Find the Boolean functions of each bit of the output.c. Optimize the Boolean functions.d. Draw the logic diagram of the optimized circuits.e. Write the VHDL code of the logic diagrams by using “Dataflow modeling” method f. Simulate the circuits that you have designed in 1.e. Prepare a simulation waveform for you report.g. Produce the RTL schematic for the circuit that you have designed in 1.e.
- Find F(A,B,C,D) for the segment "e" of a BCD-to-7 segment Decoder a. express as a Boolean as a function of A,B,C,D b. Draw the logic diagram of the function F c. Using a K-map simply F in P.O.S. form d. Draw the logic diagram of the reduced from e. Which logic diagram has lowest gate input count?parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.A shaft position encoder has 4 output. The outputs corresponding to each position are given in thetable below. It is desired to design a circuit thatshaft position between and → the output f=1at the other position → f=0The values not determined by the shaft position will be taken as 0.a) Fill the truth table. b) Reduce the output function as sum of minterms using Karnaugh map. c) Realize this function using logic gates.
- Minimize the Boolean expression F=AB’C’+C’D+BD’+A’C using K -map and implement the logic circuit using NAND gates only.A OR1 B NAND1 P- AND1 Q2.1 Boolean Aigebra in Verilog Create a module in Verilog implementing the above circuit as faithfully as possible. In particular, use three assign statements, one for each logic gate.With the following functions use a 4:1 multiplexer(mux) and minimum number of extra gates. Remember that to create the inverse of an input variable (i.e., A’, B’, etc.), you need to use an inverter. Hint:remember that you may need to try different variables on the select lines (i.e., A and B, or B and C, or A and C) to find the solution with the minimum number of extra gates. Implement each of the functions from from the above question using a 2:1 multiplexer(mux) and a minimumnumber of extra gates. Hint:remember that you may need to try different variables (i.e., A or B or C) on the select line to find the solutionwith the minimum number of extra gates. please explain in detail with a truth table as well as the schematics using a MUX.