8. In catchment, the following 1-hr UH due to 1mm effective rainfall is known: Time (hr) QUH(m3/s) 0 0 2 2 1 3 FH) = Pc + (B-fo) 3 1 4 3 A- Estimate the direct runoff if the effective rain fall during 1-hr is 5mm. B- Estimate the direct runoff is the effective rainfall is 5mm during the first hour and 10mm during the second.

8. In catchment, the following 1-hr UH due to 1mm effective rainfall is known: Time (hr) QUH(m3/s) 0 0 2 2 1 3 FH) = Pc + (B-fo) 3 1 4 3 A- Estimate the direct runoff if the effective rain fall during 1-hr is 5mm. B- Estimate the direct runoff is the effective rainfall is 5mm during the first hour and 10mm during the second.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

QUESTIONS The initial rainfall intensities of a storm during dry weather flow are 12, 16, 22, 45, 42, 38, 29, 15, 18, 25, 42, 38, 24, 12 and 3 mm/hr at 20 minutes interval. The area of basin is 750 km² and p index is 18 mm/hr. What will be the runoff volume of the basin, if the initial abstraction is 10 mm?
It rains 3.0 in on a 20 acre watershed. What is the volume of runoff if 30% of the watershed area is a lake, and infiltration on the remaining soil is estimated at 1.0 in? Express your answer in ft³. Assume the lake level is low and does not contribute to runoff (i.e. the lake only serves as storage space).
CORRECT ANSWER ALREADY PROVIDED PLEASE SHOW COMPLETE SOLUTION.
4-Calculate the amount of rain falling (storm water) on a water shed area, if you know the following: 1- Inlet time of flow = 6 min. 2- Travel (flow) time =7 min. 3- Runoff coefficient = 0.40 4- Water shed area = 10 ha.
Over a basin of area 333 km², there was a storm for 6 h with a uniform intensity of 2 cm/h. The observed runoff was 20x106 m³. The average rate of infiltration for the basin was
For a catchment in India, the mean monthly temperatures are given. Estimate the runoff and annual runoff coefficient by Khosla’s method.
Q.24 Over a basin of area 333 km², there was a storm for 6 h with a uniform intensity of 2 cm/h. The observed runoff was 20×106 m³. The average rate of 3 infiltration for the basin was A 5 mm/h B 10 mm/h C 20 mm/h D 40 mm/h
.
Net Storm Rainfall Example 2-1 Rain falls as shown in the rainfall hyetograph (intensity Vs. time) in Fig. E2-1 (a). The o index for the Storm is 0.5 in./hr and is constant over 5 hr. Plot the net rainfall on the hydrograph (flow vs. time) given in Fig. E2-1 (a). Determine the total volume of runoff and the watershed area. 1cfs = 1.008 ac-in/hr 2.0 1.5 1.0 0.5 1 3. 4 Time (hr) 700 600 500 400 300 200 100 4 8 12 16 20 24 Time (hr) Time (hr) Q (cfs) Volume (cfs-hr) 0-2 2-4 4-6 6-8 8-10 10-12 12-14 14-16 16-18 18-20 20-22 22-24 24-26 16 Q (cfs) iT (in./hr)
Q2. Two storms having duration of 4-hv and 2.hr respectively. If the rainfall excess values for the two storms were 2cm f 3cm respectively occurs Successive calculate the resulting direct runoff hydrographif the 2-hr UH For the Catchment is given below Time hr 2 4 G 10 12 14 16 18 2hr UH 25 50 75 125 100 60 20
B) The rates of rainfall for the successive 30 min period of a 3-hour storm are: 1.6, 3.6, 5.0, 2.8, 2.2, 1.0 cm/hr. The corresponding surface runoff' is estimated to be 3.6 cm. Establish the -index and its coefficient of runoff.
Along a day, precipitation is monitored four times with equal time intervals. The recorded data were 10, 12, 16, 8 mm for a catchment has an area of 3000m2. If the measured runoff in this day was 90m3, the infiltration rate is equal to