8. If the distance between a spacecraft and Saturn increases by a factor of three, the magnitude of Saturn's gravitational field strength at the position of the spacecraft ... decreases by a factor of 1/3 increases by a factor of 3 decreases by a factor of 1/9 a) b). c) d) increases by a factor of 9
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- We all know the Earth exerts gravity on us, but other objects in the solar system also pull on us. In the following series of problems we will investigate how strong gravity is for a person standing on the surface of the Earth from various objects in the solar system. You can answer the following series of questions using Newton's Law of Gravity; use the units given and the Gravitational Constant, G = 6.67 ×10 -11 m 3 /kg/s 2 . 9.What is the force of gravity due to the Earth on a 60.0 kg ASTR 110 student standing on the equator during Spring Break. DATA: Equatorial radius of the Earth 6.378 ×106 meters ; mass of the Earth 5.98×1024 kgusing the right formula: Fg = (G M1 M2 / d^2) .What is the best answer regarding what's true about the gravitational force? It has the unit of Newtons. It acts on both masses as a Newton's 3rd Law pair. It decreases with distance like an inverse square law. All the answers are correct.1. A 104 kg person and their 10 kg dog are 12.5 m away from each other. If you approximate them both as perfectly spherical what if the attractive gravitational force between them? Use G = 6.67×10-11 N-m²/kg² Enter to 3 significant figures Fa grav 4.44×10 11X N No, that's not the correct answer.
- a and bQuestion 6 Calculate the ratio of the tidal acceleration due to the Sun and the Moon at the surface of the Earth using rroSUN = 1. 5 × 10" m, MSUN = 2 × 10° kg,rtomooN = 4 × 10°m, andMMOON = 7x 104kg, andrEARTH = 6, 400, 000m. %3D 0.5 0.75 0.00002a). Explain why you cannot feel the force of gravity from a car, even though the mass of the car is so great that you cannot lift it. b) Why is it impossible to keep a satellite in a geosynchronous orbit around Antarctica?
- A 2,200 kg satellite orbits the Earth at an altitude equal to half the Earth's radius. a. Determine the satellite's orbital velocity. b. Determine the satellite's period of revolution in minutes. c. Calculate the satellite's gravitational force at this altitude. d. Calculate the satellite's centripetal acceleration.20. What is the gravitational force of attraction between two 60kg and boy girl sitting 2 m apart? Will their attraction increase or decrease when they are at a distance of 1 m apart? D= 2m, m1 -60 kg, m2 =60kg (G = 6.67 × 1011 Nm2kg-2), F= G (m1m2)/d27
- 10). Two spheres are placed 2m apart. They are fixed in place so that they cannot move. Someone takes a third object and slowly move it into place near them, as shown in the figure. M1 = 500 kg, M2 = 200 kg, and M3 = 100 kg.a). What speed would the third sphere (M3) need to be given to escape from the gravitational effects of the other two spheres?b). Once the third object is in place, what is the net force (magnitude and direction) on the third object?a) i. b) i. Define gravitational field strength at a point. Determine the mass of the Earth assuming that it is a uniform sphere of radius 6378 km and that the gravitational field strength at the Earth's surface is 9.81 N kg¹¹. Determine the average density of the Earth. iii. Use the mass of the Earth as calculated in part b)i to determine the gravitational field strength due to the Earth at a distance of 3.5 x 108 m from the centre of the Earth. ii. iv. Consider a point X a distance of 3.5 x 108 m from the centre of the Earth and which lies on the line joining the centre of the Earth to the centre of the Moon. c) i. ii. At X the gravitational field strength due to the Moon is equal but opposite to that of the Earth. The mass of the Moon is 7.4 x 10²2 kg. Determine the distance from the centre of the Moon to X and hence determine the distance between the centres of the Earth and Moon. Determine the time in Earth years for the planet Jupiter to complete one orbit of the Sun. Take 1…Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.4 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What is the force of attraction between Mars and the satellite? 2.)What speed should the satellite have to be in a perfectly circular orbit? 3.)How much time does it take the satellite to complete one revolution?