8. Given the following equations: -Do- (NOR) -Do- (NAND) Build the circuit with only NOR Gates. B- B S=AB+ AB = AB + AA+AB + BB = 4(A + B) + B(A + B) = (4+ 8) (A + B) =A+B+(A + B) C=A.B=AB=A+B A AB Donor pland to
8. Given the following equations: -Do- (NOR) -Do- (NAND) Build the circuit with only NOR Gates. B- B S=AB+ AB = AB + AA+AB + BB = 4(A + B) + B(A + B) = (4+ 8) (A + B) =A+B+(A + B) C=A.B=AB=A+B A AB Donor pland to
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Number 8 tell me what I did wrong also Don't use ChatGPT it didn't work show your work hand written thank you and God bless

Transcribed Image Text:3. Simplify the equation
4. Simplify the equation (A + B)(A+C)(A + D) using Boolean algebra.
5. Given the following equation (A+B)C + DE. Build the circuit by only using N
6. Given the following equation A'B'CD + A'BCD + ABCD + AB'CD + ABC'D' +
map. Once it is simplified, draw the circuit.
7. Simplify the expression: AB'C + A'BC' + AB
8. Given the following equations:
=D-(NOR)
-Do- (NAND)
Build the circuit with only NOR Gates.
At
A
B
B
S=A-B+ AB
= AB+ AA+ AB + BB
= 4(A + B)+ B(A + B)
= (A + B) (A + B)
=A+B+(A+B)
C=AB=AB=A+B
9. Given the following equations:
DG (NAND)
Donor
Do Nand
S = AB + AB
-
Build the circuit with only NAND Gates.
AB
AB+ AA+ AB + BB
A(A+B) + B(A + B)
C=AB=
no
=AAB BAB
A.B
AB=A+B
2
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