8. For the oxidation-reduction reaction: S406(aq) + Cr+(aq) Cr (aq) + S202 (aq), -> the appropriate half reactions are: Cr+ E° = -0.50 V. 2S2032 E° = 0.17 V; Crt + e- Balance the redox equation and calculate E° and K (at 25 °C. S406 + 2e-

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**Redox Reaction and Standard Electrode Potentials**

**Problem 8:**

For the oxidation-reduction reaction:

\[ \text{S}_4\text{O}_6^{2-} \text{(aq)} + \text{Cr}^{2+} \text{(aq)} \rightarrow \text{Cr}^{3+} \text{(aq)} + \text{S}_2\text{O}_3^{2-} \text{(aq)}, \]

the appropriate half reactions are:

1. \[ \text{S}_4\text{O}_6^{2-} + 2e^- \rightarrow 2\text{S}_2\text{O}_3^{2-} \] 
   \[ E^\circ = 0.17 \, \text{V} \]

2. \[ \text{Cr}^{3+} + e^- \rightarrow \text{Cr}^{2+} \]
   \[ E^\circ = -0.50 \, \text{V} \]

**Instructions:**

- Balance the redox equation.
- Calculate \( E^\circ \) and \( K \) at \( 25^\circ \text{C} \).
Transcribed Image Text:**Redox Reaction and Standard Electrode Potentials** **Problem 8:** For the oxidation-reduction reaction: \[ \text{S}_4\text{O}_6^{2-} \text{(aq)} + \text{Cr}^{2+} \text{(aq)} \rightarrow \text{Cr}^{3+} \text{(aq)} + \text{S}_2\text{O}_3^{2-} \text{(aq)}, \] the appropriate half reactions are: 1. \[ \text{S}_4\text{O}_6^{2-} + 2e^- \rightarrow 2\text{S}_2\text{O}_3^{2-} \] \[ E^\circ = 0.17 \, \text{V} \] 2. \[ \text{Cr}^{3+} + e^- \rightarrow \text{Cr}^{2+} \] \[ E^\circ = -0.50 \, \text{V} \] **Instructions:** - Balance the redox equation. - Calculate \( E^\circ \) and \( K \) at \( 25^\circ \text{C} \).
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