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8. Find the general solution of (x2 + y2 + 1) dx + (x2 – 2xy) dy = А. х2 - у? - ху — 1%3D Сх В. х2 + у2 - ху — 1 %3D Сх %3! C. x2 + y2 + xy - 1 = Cx D. x2 - y2 + xy - 1 = Cx www

8. Find the general solution of (x2 + y2 + 1) dx + (x2 – 2xy) dy = А. х2 - у? - ху — 1%3D Сх В. х2 + у2 - ху — 1 %3D Сх %3! C. x2 + y2 + xy - 1 = Cx D. x2 - y2 + xy - 1 = Cx www

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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8. Find the general solution of (x2 + y2 + 1) dx + (x- 2xy) dy = 0 А. х2 - у2 - ху - 1 %3D Сх В. х2 + у2 - ху — 1 %3D Сх C. x2 + y2 + xy - 1 = Cx D. x2 - y2 + xy - 1 = Cx www
Transcribed Image Text:8. Find the general solution of (x2 + y2 + 1) dx + (x- 2xy) dy = 0 А. х2 - у2 - ху - 1 %3D Сх В. х2 + у2 - ху — 1 %3D Сх C. x2 + y2 + xy - 1 = Cx D. x2 - y2 + xy - 1 = Cx www
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