Sure! Here is the transcribed content from the provided image:---**8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: O = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person’s blood group is:**a) AB?b) Either A or B?c) O?d) Not O?---To solve these problems, you can use the principles of probability. Each probability is calculated by dividing the number of people with the specified blood type by the total number of people (15 in this case).- **a) Probability of AB:** There is 1 person with blood type AB. So, the probability is \( \frac{1}{15} \).- **b) Probability of Either A or B:** There are 5 people with blood type A and 6 people with blood type B, making a total of 11. So, the probability is \( \frac{11}{15} \).- **c) Probability of O:** There are 3 people with blood type O. So, the probability is \( \frac{3}{15} \) which simplifies to \( \frac{1}{5} \).- **d) Probability of Not O:** There are 12 people who do not have blood type O (A, B, and AB combined). So, the probability is \( \frac{12}{15} \) which simplifies to \( \frac{4}{5} \).

Given that Total number of people (n) = 15 Person with O blood group = 3 Persons with A blood group…

8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: 0 = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person's blood group is:

8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: 0 = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person's blood group is:

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section8.7: Probability

Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...

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---

**8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: O = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person’s blood group is:**

a) AB?

b) Either A or B?

c) O?

d) Not O?

---

To solve these problems, you can use the principles of probability. Each probability is calculated by dividing the number of people with the specified blood type by the total number of people (15 in this case).

- **a) Probability of AB:** There is 1 person with blood type AB. So, the probability is \( \frac{1}{15} \).

- **b) Probability of Either A or B:** There are 5 people with blood type A and 6 people with blood type B, making a total of 11. So, the probability is \( \frac{11}{15} \).

- **c) Probability of O:** There are 3 people with blood type O. So, the probability is \( \frac{3}{15} \) which simplifies to \( \frac{1}{5} \).

- **d) Probability of Not O:** There are 12 people who do not have blood type O (A, B, and AB combined). So, the probability is \( \frac{12}{15} \) which simplifies to \( \frac{4}{5} \).

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