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8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: 0 = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person's blood group is:

8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: 0 = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person's blood group is:

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 6ECP: In Pennsylvania’s Cash 5 game, a player chooses five different numbers from 1 to 43. If these five...
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Sure! Here is the transcribed content from the provided image: --- **8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: O = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person’s blood group is:** a) AB? b) Either A or B? c) O? d) Not O? --- To solve these problems, you can use the principles of probability. Each probability is calculated by dividing the number of people with the specified blood type by the total number of people (15 in this case). - **a) Probability of AB:** There is 1 person with blood type AB. So, the probability is \( \frac{1}{15} \). - **b) Probability of Either A or B:** There are 5 people with blood type A and 6 people with blood type B, making a total of 11. So, the probability is \( \frac{11}{15} \). - **c) Probability of O:** There are 3 people with blood type O. So, the probability is \( \frac{3}{15} \) which simplifies to \( \frac{1}{5} \). - **d) Probability of Not O:** There are 12 people who do not have blood type O (A, B, and AB combined). So, the probability is \( \frac{12}{15} \) which simplifies to \( \frac{4}{5} \).
Transcribed Image Text:Sure! Here is the transcribed content from the provided image: --- **8. Fifteen persons reporting to a Red Cross center one day are typed for blood, and the following counts are found: O = 3, A = 5, B = 6, AB = 1. If one person is randomly selected, what is the probability that this person’s blood group is:** a) AB? b) Either A or B? c) O? d) Not O? --- To solve these problems, you can use the principles of probability. Each probability is calculated by dividing the number of people with the specified blood type by the total number of people (15 in this case). - **a) Probability of AB:** There is 1 person with blood type AB. So, the probability is \( \frac{1}{15} \). - **b) Probability of Either A or B:** There are 5 people with blood type A and 6 people with blood type B, making a total of 11. So, the probability is \( \frac{11}{15} \). - **c) Probability of O:** There are 3 people with blood type O. So, the probability is \( \frac{3}{15} \) which simplifies to \( \frac{1}{5} \). - **d) Probability of Not O:** There are 12 people who do not have blood type O (A, B, and AB combined). So, the probability is \( \frac{12}{15} \) which simplifies to \( \frac{4}{5} \).
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