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8. During an ice show, a 60.0-kg skater leaps with an initial of 4.00 m/s into the air and is caught by an initially stationary 75.0-kg skater. How much kinetic energy (KE) is lost (enter your energy in Joules)? Assume the friction force is negligible. (Hint: First find the final common velocity and subtract the final KE from the initial KE) Ans:267 O Stetionary Stéater in Mivit Mq Vz = Mivit Mz Vg 13D object m,V, Miv, = (mit my) v'→ (Mit mz) object mivi %3D (Mi+m2) Wh м 4.00 T2 Contale Change in KE = miv,-(itmjue miV, AK= Lost in KE = бод 75.0k 60-00 (cg

8. During an ice show, a 60.0-kg skater leaps with an initial of 4.00 m/s into the air and is caught by an initially stationary 75.0-kg skater. How much kinetic energy (KE) is lost (enter your energy in Joules)? Assume the friction force is negligible. (Hint: First find the final common velocity and subtract the final KE from the initial KE) Ans:267 O Stetionary Stéater in Mivit Mq Vz = Mivit Mz Vg 13D object m,V, Miv, = (mit my) v'→ (Mit mz) object mivi %3D (Mi+m2) Wh м 4.00 T2 Contale Change in KE = miv,-(itmjue miV, AK= Lost in KE = бод 75.0k 60-00 (cg

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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8. During an ice show, a 60.0-kg skater leaps with an initial of 4.00 m/s into the air and is caught by an initially stationary 75.0-kg skater. How much kinetic energy (KE) is lost (enter your energy in Joules)? Assume the friction force is negligible. (Hint: First find the final common velocity and subtract the final KE from the initial KE) Ans:267 O Stetionary Stéater in Mivit Mq Vz = Mivit Mz Vg 13D object m,V, Miv, = (mit my) v'→ (Mit mz) object mivi %3D (Mi+m2) Wh м 4.00 T2 Contale Change in KE = miv,-(itmjue miV, AK= Lost in KE = бод 75.0k 60-00 (cg
Transcribed Image Text:8. During an ice show, a 60.0-kg skater leaps with an initial of 4.00 m/s into the air and is caught by an initially stationary 75.0-kg skater. How much kinetic energy (KE) is lost (enter your energy in Joules)? Assume the friction force is negligible. (Hint: First find the final common velocity and subtract the final KE from the initial KE) Ans:267 O Stetionary Stéater in Mivit Mq Vz = Mivit Mz Vg 13D object m,V, Miv, = (mit my) v'→ (Mit mz) object mivi %3D (Mi+m2) Wh м 4.00 T2 Contale Change in KE = miv,-(itmjue miV, AK= Lost in KE = бод 75.0k 60-00 (cg
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