8. Describe the nature of the IMF (dipole-dipole) holding ICI (iodine-chlorine) molecules together in the liquid state. Include a labeled drawing as part of your explanation.

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**Text Transcription for Educational Website:**

Both HF and F2 share electrons, forming covalent bonds. HF is a polar covalent molecule, due to greater electronegativity causing the electrons to be closer to the atom. F2 is non-polar.

8. Describe the nature of the IMF (dipole-dipole) holding ICl (iodine-chlorine) molecules together in the liquid state. Include a labeled drawing as part of your explanation.

9. Complete the table.  
For each pair of molecules circle the one with the higher boiling point. Your answer should be based on the number of electrons in each molecule and the polarity of each molecule.

|      Molecules     | # e⁻ | Polar |   Type of IMF    |
|:-------------------:|:---:|:-----:|:-----------------:|
| Pair 1            |     |       |                   |
|       CH₄         |  10 |  Yes  |       London      |
|       SiH₄        |  18 |  Yes  |       London      |
| Pair 2            |     |       |                   |
|     CH₂Cl₂       |  42 |  Yes  |       London      |
|     CCl₄         |     |  No   |   Dipole-Dipole   |

**Notes on Diagrams and Graphs:**

- **Diagrams Not Shown**: A labeled drawing of the dipole-dipole interaction in ICl could include the positive and negative ends of the ICl molecule aligning to visualize the attraction between oppositely charged poles.

- **Table**: This table provides a comparison of different molecules, highlighting the number of electrons, whether they are polar, and their associated intermolecular forces (IMFs). The term "London" refers to London dispersion forces, a type of IMF, while "Dipole-Dipole" indicates another type of IMF that can exist between polar molecules.
Transcribed Image Text:**Text Transcription for Educational Website:** Both HF and F2 share electrons, forming covalent bonds. HF is a polar covalent molecule, due to greater electronegativity causing the electrons to be closer to the atom. F2 is non-polar. 8. Describe the nature of the IMF (dipole-dipole) holding ICl (iodine-chlorine) molecules together in the liquid state. Include a labeled drawing as part of your explanation. 9. Complete the table. For each pair of molecules circle the one with the higher boiling point. Your answer should be based on the number of electrons in each molecule and the polarity of each molecule. | Molecules | # e⁻ | Polar | Type of IMF | |:-------------------:|:---:|:-----:|:-----------------:| | Pair 1 | | | | | CH₄ | 10 | Yes | London | | SiH₄ | 18 | Yes | London | | Pair 2 | | | | | CH₂Cl₂ | 42 | Yes | London | | CCl₄ | | No | Dipole-Dipole | **Notes on Diagrams and Graphs:** - **Diagrams Not Shown**: A labeled drawing of the dipole-dipole interaction in ICl could include the positive and negative ends of the ICl molecule aligning to visualize the attraction between oppositely charged poles. - **Table**: This table provides a comparison of different molecules, highlighting the number of electrons, whether they are polar, and their associated intermolecular forces (IMFs). The term "London" refers to London dispersion forces, a type of IMF, while "Dipole-Dipole" indicates another type of IMF that can exist between polar molecules.
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