8. Compute the volume V of the solid region below the surface z = 2xy + 3x² and above the triangle with vertices at the points (0, 0, 0), (0, 1, 0) and (1, 1,0) on the x, y plane. → (A) V = (B) V = (C) V = (D) (E) V = V = 3 1 3 3 4 4 113 2 3 Solution. Let D = {(x, y), 0≤ y ≤ 1,0 ≤ x ≤y}. Then, LL [² 2xy + 3₂², 0 0 V = J₂ D 2xy +3x² dA: -1 = [ ₁² [2 ² y + 2²³²] = = dy = f₁" 2 y ³ dy = 1 4 y dx dy 2 0 = 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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8.
Compute the volume V of the solid region below the surface z = 2xy +3x² and above
the triangle with vertices at the points (0, 0, 0), (0, 1, 0) and (1, 1, 0) on the x, y plane.
→ (A) V
(B) V =
(C) V
(D) V
(E)
=
V
=
||
=
312
3
414 416
1
Solution. Let D = {(x, y), 0 ≤ y ≤ 1, 0≤x≤ y}. Then,
1
V= /[ 2xy +32²dA= [[ 2xy +3a²dr dy
= 6²
1
= [₁²₁ [2² y + 2²³¹] dy =
| 2y³ dy = [4] = ²
0
ال
Transcribed Image Text:8. Compute the volume V of the solid region below the surface z = 2xy +3x² and above the triangle with vertices at the points (0, 0, 0), (0, 1, 0) and (1, 1, 0) on the x, y plane. → (A) V (B) V = (C) V (D) V (E) = V = || = 312 3 414 416 1 Solution. Let D = {(x, y), 0 ≤ y ≤ 1, 0≤x≤ y}. Then, 1 V= /[ 2xy +32²dA= [[ 2xy +3a²dr dy = 6² 1 = [₁²₁ [2² y + 2²³¹] dy = | 2y³ dy = [4] = ² 0 ال
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