8. B. In the figure above AD is perpendicular to BC, AD = DB. AC = 4cm and angle CAD = 30°. Find AB. 1A (ithout ucing a calculator write down (i) Cos 60° (ii) Sin 60° (iii) Tan 45° 4 cm 30°
8. B. In the figure above AD is perpendicular to BC, AD = DB. AC = 4cm and angle CAD = 30°. Find AB. 1A (ithout ucing a calculator write down (i) Cos 60° (ii) Sin 60° (iii) Tan 45° 4 cm 30°
8. B. In the figure above AD is perpendicular to BC, AD = DB. AC = 4cm and angle CAD = 30°. Find AB. 1A (ithout ucing a calculator write down (i) Cos 60° (ii) Sin 60° (iii) Tan 45° 4 cm 30°
Transcribed Image Text:(1)
Cos 120 (1) Sin 250° (i) Tan - 400° (iv) Cos- 20
Given that tan 0=
and that 0 lies between 0° and 180° , find without using
tables or a calculator, the value of Sin 0- Cos 0.
5. From the top of a vertical building 20 m tall, the angle of depression of a mark on a
horizontal ground is 18°. Find the distance of the mark from the base of the building.
6. Amos who is 1.5m tall first measures the angle of elevation of the top of a 35m
vertical building as 5°while standing at point A. He them walks towards the building
in a straight line to another point B and measures the angle of elevation of the top
of the building as 10°. Calculate the distance between A and B.
7. ABC is a triangle in which AB = 6.5 cm , AC = 4.2 cm and angle BAC = 54°.
Find (i) length of BC (ii) the area of the triangle.
8.
D
In the figure above AD is perpendicular to BC, AD = DB. AC = 4cm and angle CAD =
30°. Find AB.
9. Without using a calculator write down (i) Cos 60° (ii) Sin 60°
(i) Sin 70° = Cos
(iii) Tan 45°
10. Fill in the missing angle
%3D
(ii) Cos 50° = Sin
4 cm
30°
Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).
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