8. A stress element dia is shown in fig. Compute the normal. t shear stress on plane. Am. (a) страж 2мри. 2mPa.. 3 ·3MPa. zny! 2Mla. Toni વર 3 MPa. 12MPa. A → (MPa..

Q: Problem 4 The horizontal force of p 85 kN acts at the end of the plate. The plate has a thickness of…

A:

Q: If the output torque on the CD shaft is T ́ = 75 N-m and the motor rotates at 175 rpm, determine the…

A: Given for CD shaft    diameter d2=35 mm, radius of gear R2=125 mmand torque T2=75 N-mfor EA shaft…

Q: A 12ft cantilever beam is subjected a 180 lb/ft uniform load and a vertical support of 1200 lb on…

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Q: 2-22. The triangular plate is fixed at its base, and its apex A is given a horizontal displacement…

A:

Q: The bell crank is in equilibrium for the forces acting in rods (1) and (2). The bell crank is…

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Q: The force P is applied at d = 50 mm from the bottom as shown. Compute the normal stress at section…

A: Given: The value of d is 50 mm. The value of P is 85 kN. Consider the figure,

Q: Q1). Determine the maximum stress produced by the loads and create the shear and moment diagram.

A: ∑MA = 0 = - By×10 + 200×4×2By = 160010 = 160 N∑FY = 0Ay + By = 200×4Ay = 800 -160 Ay = 640 N∑FX = 0…

Q: *2-24. The triangular plate is fixed at its base, and its apex A is given a horizontal displacement…

A: The triangular plate with dimensions as shown in the figure below,Horizontal displacement,…

Q: 4Kips 10 KIPS 0.5 in.diam. 1in diam. lokips 8kips 0.75 in diam.

A: for First segment Dia = 0.5 in.     Load = 4kips for Second segment Dia = 1in.    Load = 14 kips…

Q: The couple M = 78 kip-in. is app section shown in a plane formin vertical. Determine the stress at…

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Q: Determine the f. unknowns on the beam shown below using Conjugate - Beam Method Consider 250 mm x…

A: Note:- Hi! Thank you for the question, As per the honor code, we are allowed to answer three…

Q: The internal shear force V at a certain section of an aluminum beam is 40 kN. The beam's centroid is…

A: V = 40 kN, Location of Centroid from bottom = 54.4 mm, Moment of Inertia, Iz = 398300 mm4

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.