**Problem 8:** A mass \( m_1 = 6.50 \, \text{kg} \) is connected by a light string that passes over a pulley of mass \( M = 13.5 \, \text{kg} \) to a mass \( m_2 = 12.0 \, \text{kg} \) sliding on a horizontal surface (see figure). The coefficient of kinetic friction between the mass \( m_2 \) and the surface is 0.25. There is no slippage between the string and the pulley. What is the magnitude of the tension that is acting on mass \( m_2 \)? (The moment of inertia of the pulley is \(\frac{1}{2}Mr^2\))**Answer:** \(\_\_\_\_\) N**Diagram Description:**The diagram is a simple representation of a pulley system. It shows:- A pulley labeled \( M \) at the center.- A mass \( m_1 \) (colored in green) hanging vertically downwards from the right side of the pulley.- A mass \( m_2 \) (colored in blue) on the left side, sliding horizontally on a surface.- A light string connecting \( m_1 \) and \( m_2 \) over the pulley. The system implies that \( m_2 \) is subject to friction as it slides on the surface, influencing the tension in the string. The task is to calculate the magnitude of this tension acting on \( m_2 \).

Consider the mass m1 is moving in the downward direction with the acceleration ‘a’. The net force on…

8. A mass m, = 6.50 kg is connected by a light string that passes over a pulley of mass M = 13.5 kg to a mass m, = 12.0 kg sliding on a horizontal surface (see figure). The coefficient of kinetic friction between the mass m2 and the surface is 0.25. There is no slippage between the string and the pulley. What is the magnitude of the tension that is acting on mass m2? (The moment of inertia of the pulley is ½M²².) N m2 M m1

8. A mass m, = 6.50 kg is connected by a light string that passes over a pulley of mass M = 13.5 kg to a mass m, = 12.0 kg sliding on a horizontal surface (see figure). The coefficient of kinetic friction between the mass m2 and the surface is 0.25. There is no slippage between the string and the pulley. What is the magnitude of the tension that is acting on mass m2? (The moment of inertia of the pulley is ½M²².) N m2 M m1

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

**Problem 8:** A mass \( m_1 = 6.50 \, \text{kg} \) is connected by a light string that passes over a pulley of mass \( M = 13.5 \, \text{kg} \) to a mass \( m_2 = 12.0 \, \text{kg} \) sliding on a horizontal surface (see figure). The coefficient of kinetic friction between the mass \( m_2 \) and the surface is 0.25. There is no slippage between the string and the pulley. What is the magnitude of the tension that is acting on mass \( m_2 \)? (The moment of inertia of the pulley is \(\frac{1}{2}Mr^2\))

**Answer:** \(\_\_\_\_\) N

**Diagram Description:**

The diagram is a simple representation of a pulley system. It shows:
- A pulley labeled \( M \) at the center.
- A mass \( m_1 \) (colored in green) hanging vertically downwards from the right side of the pulley.
- A mass \( m_2 \) (colored in blue) on the left side, sliding horizontally on a surface.
- A light string connecting \( m_1 \) and \( m_2 \) over the pulley.

The system implies that \( m_2 \) is subject to friction as it slides on the surface, influencing the tension in the string. The task is to calculate the magnitude of this tension acting on \( m_2 \).

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