8. A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive 32P isotope with a half life of 14.3 days and which decays via beta emission with an energy of 1.71MEV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 9.00 J of energy into it. The other half of the solution is dispersed throughout the patients tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. (a) What is the dose (in Gy and rem) that the tumor receives? (b) What is the dose (in Gy and rem) that the rest of the patient receives?

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Chapter1: Units, Trigonometry. And Vectors
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8. A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus
atoms are the radioactive 32P isotope with a half life of 14.3 days and which decays via beta emission
with an energy of 1.71MEV. Half of the sodium phosphate solution is absorbed by the tumor and
deposits 9.00 J of energy into it. The other half of the solution is dispersed throughout the patients
tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. (a) What is the dose (in Gy and
rem) that the tumor receives? (b) What is the dose (in Gy and rem) that the rest of the patient receives?
Transcribed Image Text:8. A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive 32P isotope with a half life of 14.3 days and which decays via beta emission with an energy of 1.71MEV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 9.00 J of energy into it. The other half of the solution is dispersed throughout the patients tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. (a) What is the dose (in Gy and rem) that the tumor receives? (b) What is the dose (in Gy and rem) that the rest of the patient receives?
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