8.) A 1.000 g sample of zinc metal is dissolved in 50 mL of 6 M HCI solution and dilutedto the mark in a 250 mL volumetric flask. A 25.00 mL portion is transferred to apolarographic cell and oxygen is flushed out. A polarogram in the range 0 – 1 V (vs. theHg-pool electrode) shows a wave at E1/2 = -0.65 V, id = 32.0 units of galvanometerdeflection. A 5.00 mL portion of 5.00 x 10-4 M CDC12 solution is added directly to thepolarography cell which already contains the Zn solution, oxygen is again flushed out,and a second polarogram is taken. The wave shows the same E1/2 but the id is 77.5units. Calculate the percent by weight of Cd impurity in the Zn metal. Note: Atomic weightof Cd is 112.4 g/mole.

Given that: Mass of Zn sample = 1.000 g Volume of the sample, V1 = 25 mL Diffusion current of the…

8.) A 1.000 g sample of zinc metal is dissolved in 50 mL of 6 M HCl solution and diluted to the mark in a 250 mL volumetric flask. A 25.00 mL portion is transferred to a polarographic cell and oxygen is flushed out. A polarogram in the range 0 - 1 V (vs. the Hg-pool electrode) shows a wave at E1/2 = -0.65 V, id = 32.0 units of galvanometer deflection. A 5.00 mL portion of 5.00 x 10-4 M CdCl2 solution is added directly to the polarography cell which already contains the Zn solution, oxygen is again flushed out, and a second polarogram is taken. The wave shows the same E1/2 but the id is 77.5 units. Calculate the percent by weight of Cd impurity in the Zn metal. Note: Atomic weight of Cd is 112.4 g/mole.

8.) A 1.000 g sample of zinc metal is dissolved in 50 mL of 6 M HCl solution and diluted to the mark in a 250 mL volumetric flask. A 25.00 mL portion is transferred to a polarographic cell and oxygen is flushed out. A polarogram in the range 0 - 1 V (vs. the Hg-pool electrode) shows a wave at E1/2 = -0.65 V, id = 32.0 units of galvanometer deflection. A 5.00 mL portion of 5.00 x 10-4 M CdCl2 solution is added directly to the polarography cell which already contains the Zn solution, oxygen is again flushed out, and a second polarogram is taken. The wave shows the same E1/2 but the id is 77.5 units. Calculate the percent by weight of Cd impurity in the Zn metal. Note: Atomic weight of Cd is 112.4 g/mole.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Calculate the fraction of atom sites that are vacant for silver at (3.60x10^2) °C. Assume an energy…

Q: A 100.0 ml solution containing 0.100 M NaBr was titrated with 0.100 M AgNOz and monitored with a…

Q: Calculate the value of n if idmax= 7.008×10-6A.

A: Polarographic technique is applied for qualitative and quantitative analysis of reducible or…

Q: To find the copper content in 50 mL of sample, a titration is carried out with 0.01 M AEDT. A…

A: The objective of the question is to identify the necessary equipment and materials for a…

Q: A solution is made by combining 1.000 ml of 0.1000 M Cd(NO)2 with.000 ml. of 1.000 M HBr and 3.000…

A: The equilibrium constant can be written as the ratio of concentration of products to the…

Q: 1.A compound Y (150.0 g/mol) in a 1.00 cm quartz cell has an extinction coefficient (ε) of 23,150 at…

A: Answer to Question No:1 The energy of a photon can be calculated by the famous formula- E=hcλwhere,…

Q: +3 The absorbance of a 1.05x10° M Fe" solution was determined at 580 nm using a 2.50-cm cell. The…

Q: What is the concentration of SCN" in a solution prepared by adding 5.0 mL of 0.0020M SCN" to a test…

Q: The following measurements were recorded for standard solutions of metal complexes with EDTA using a…

Q: 2. Explain the difference between "ion product" and Kep. What conditions are necessary for the ion…

A: Ksp is solubility product constant is equlibrium constant for a solid substance dissolving in an…

Q: You wish to measure the iron content of the well water on the new property you are about to buy. You…

Q: A 0.9056 g sample of KBrO3 (MM=167.0) was dissolved in dilute HCl and treated with an unmeasured…

A: Moles of KBrO3 = 0.9056/167 = 0.00542 Moles of thiosulphate required = 6*0.005432 = 0.0325

Q: Where does the strongest IMF occur in liquid ethanol?

A: Ethanol molecule contains -OH group which have O-H bond and it take part in hydrogen bonding with…

Q: Answer part a and b

A: Cell reactions are given by, Calculation for Eocell: Reversing and multiplying the equation with 3:…

Q: 0.9056 g sample of KBrO3 (MM=167.0) was dissolved in dilute HCl and treated with an unmeasured…

A: Practical chemistry:

Q: A 50.0 mL sample containing Cd²+ and Mn²+ was treated with 41.4 mL of 0.0700 M EDTA. Titration of…

A: EDTA forms 1:1 complex with Cd+2, Mn+2 and Ca+2So number of moles of Ca+2 or Cd+2 or Mn+2 is equal…

Q: f. Predict the effect of a reduced extracelluar concentration of Na* on the magnitude of the action…

A: The objective of this question is to show the extracellular concentration of sodium ions plays a…

Q: A 50.0 mL sample containing Cd²+ and Mn²+ was treated with 60.9 mL of 0.0700 M EDTA. Titration of…

A: Volume of the sample = 50.0 mL…

Q: Vanadium has two isotopes (50V, 0.25%; 51V, 99.75%). The EPR spectrum of an aqueous solution of…

Q: At 21 °C, a solution of 12 mL each of 0.00200 M Fe3+ and 0.001000 M SCN- was mixed and brought to…

A: The given reaction is: Fe3+(aq) + SCN-(aq) → Fe(SCN)2+(aq) Here the product, Fe(SCN)2+(aq) is…

Q: Water from Jordan Lake was analyzed for its Fe³+ content. A 20.0-mL sample of lake water was…

A: First, we have to calculate the value of the molar absorptivity constant, ε using the concentration…

Q: Application of Spectroscopy: You wish to measure the iron content of the well water on the new…

A: Absorbance is directly proportional to the concentration of the colored sample as per Lambert-beer's…

Q: A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 65.1 mL of 0.0400 M EDTA. Titration of…

A: Volume of EDTA = 65.1 mL Initial Molarity of EDTA = 0.04 M Initial moles of EDTA- Moles = Molarity…

Q: Ti3+ is to be generated in 0.10 M HCIO, for coulometric reduction of azobenzene. TiO2+ + 2 H+ +e¯…

Q: A 5.323 g of dried eggshell is transferred to a 250-mL beaker and dissolved in 25 mL of 6 M HCl. The…

Q: Describe two applications of Potentiometric analysis

A: Potentiometric analysis is a process in which the potential of a substance is measured with respect…

Q: According to the table below, Zn- has a slightly larger mobility than Na" How can you explain that?

A: Ionic mobility: It is defined as the speed gained by ions moving through gas under a unit electric…

Q: Give a clear handwritten answer...

Q: Give only typing answer with explanation and conclusion A solution of Tryptophan has an absorbance…

A: In this question, we will determine the concentration of the solution using beer-lambert law

Q: The v (NO) values irn [Ru(bpy)2 (NO)X]?+ are X =MECN, Z = 3, v (NO) = 1970 cm -1. %3D X = Cl, Z = 2,…

A: π- back bonding in transition metal complexes: ligand donates σ-electron density to the metal and…

Q: A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point…

Q: 2. (a) The v(CO) of isoelectronic series [Mn(CO)], [Cr(CO)] and [V(CO) are 2090 cm³¹ 2000cm¹ and…

A: This Question is based upon Inorganic IR Spectroscopy.

Q: The following cell was found to have a measured potential of 0.42 V: SCE||Ba2+(1.0x10-4)|membrane…

A: Saturated calomel electrode|| Ba2+|membrane electrode of Ba2+ Reaction at anode: 2Hg(l) + 2Cl-…

Q: An ampoule with 290 mg N₂04 was introduced into a quartz vessel of volume 500.0 mL. The vessel was…

A: To solve this problem, we need to use the ideal gas law to relate the pressure, temperature, and…

Q: Explain the principle behind FRAP (ferric reducing antioxidant power) assay. What about ABTS Assay?

A: We have to tell principle behind FRAP and also about ABTS Assay.…

Q: A 50.0 mL sample containing Cd²+ and Mn²+ was treated with 57.3 mL of 0.0700 M EDTA. Titration of…

Q: (ar Pol ~ ~ Ru (bpy) 2 Cl2 shows two redox couples at 0.3 V and 1.9 V. versus SCE whereas [Ru (bpy)…

Q: A cyanide solution with a volume of 13.87 mL was treated with 24.00 mL of Ni+ solution (containing…

A: Concentration of CN- can be determined from the amount of Ni2+ used in the titration of CN-.

Q: 1. Write two possible defect reactions and corresponding mass action expressions for the following:…

A: Given:Equilibrium constant is the ratio of concentration of products to the concentration of…

Question

8.) A 1.000 g sample of zinc metal is dissolved in 50 mL of 6 M HCI solution and diluted
to the mark in a 250 mL volumetric flask. A 25.00 mL portion is transferred to a
polarographic cell and oxygen is flushed out. A polarogram in the range 0 – 1 V (vs. the
Hg-pool electrode) shows a wave at E1/2 = -0.65 V, id = 32.0 units of galvanometer
deflection. A 5.00 mL portion of 5.00 x 10-4 M CDC12 solution is added directly to the
polarography cell which already contains the Zn solution, oxygen is again flushed out,
and a second polarogram is taken. The wave shows the same E1/2 but the id is 77.5
units. Calculate the percent by weight of Cd impurity in the Zn metal. Note: Atomic weight
of Cd is 112.4 g/mole.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Step 8

Trending now

This is a popular solution!

Step by step

Solved in 8 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

A 5.00 mL sample that contains the borate ion {B4O5(OH)42-} at 35oCwas transferred to an Erlenmeyer flask and diluted with water to ~25 mL. This solution was titrated with 20.9 mL of 0.21 M HCl to the bromocresol green endpoint. What is the Ksp for the borax? Report your Ksp value to 3 decimal places.
Please answer correct.
A 50.00mL sample with BaCl2 was diluted to 650 mL. Aliquots of 100.00 mL of this solution were analysed using Mohr and Volhard methods. The following data were obtained. Volhard method: Volume of AgNO3 = 100mL; Volume of KSCN = 18.25mL Mohr Method: volume of AgNO3: sample = 27.80mL (blank) = 0.30mLWhat is the %BaCl2 using Mohr and Volhard Method. Concentration of KSCN: 0.04000M Concentration of AgNO3: 0.03000M
Far the cell: pt/ Hz clatuy / NaOH Com)/ Hg0 cs)/ Hg cel -0.924V 854V 198K eatcutate standard eledromotive force Eas K write the eleetreds reaehions and the ett reaction So calculate the electromotive force at s08 K the change in inthalpy (AH)= and, what happen to electramotive forcewihen adokd few amount of nitrie acid to equitalent to the base Hg/Hg when - 35 kcal to cell reachin NaoH partially 2
Please solve the question as quickly as possible, thank you
Give the solutions of the following;1. Calculate the effective absorptivity and molar absoptivity for manganese is a potassium permanganate solution that contains 0.10g of manganese in 100 mL has an absorbance of 0.434 using a 1.5 cm cell at a wavelenght of 550 nm. Molar Mass: Mn=54.94Answer: Effective absorptivity= 2.89 cm-1 g-1 L ; mOLAR ABSOPTIVITY= 159 cm-1 mol-1L 2. Manganese is determined colorimentrically as permanganate by measuring the absoprtion of monochromatic green light. A standard solution in an absoption cell 5.00 cm long absorbs 10.0% of the light, while an unknown sample in a cell 1.00 cm long absorbs 50.0% of the light. The standard solution contains 2.00 mg of Mn per liter. What is the concentration (g/L) of the Mn in the unknown? Ans= 0.0657 g/L3. The drug tolbutamine (mm=270) has a molar absorptivity of 703 AT 262 nm. One tablet is dissolved in water and diluted to a volume of 2L. If the solution exhibits an absorbance in the UV region at 262 nm equal to 0.678…
1. Explain how to calculate liquid junction potential (VEJ) 2. Cell concentration of amalgam with cell diagram: Pb (Hg) (α1) / Pb2+ (α) / Pb (Hg) (α2). Write down:a. Cell reactionsb. calculate the price of E0 and Esel
In XPS spectrum of materials, all binding energy should be corrected using a standard bonding energy value of carbon 1s. Explain why and how carbon (C) charge correction must be executed prior fitting the XPS spectrum (If C exp = 288.0eV and C standard = 284.6eV)
State in your own words what the abbreviation α Y4- means with regards to EDTA speciation in water. Calculate α Y4- for EDTA at (a) pH 3.50 and (b) 10.50.
A 50.0 mL sample containing Cd2+ and Mn²+ was treated with 48.0 mL of 0.0600 M EDTA. Titration of the excess unreacted EDTA required 14.7 mL of 0.0290 M Ca²+. The Cd²+ was displaced from EDTA by the addition of an excess of CN-. Titration of the newly freed EDTA required 10.3 mL of 0.0290 M Ca²+. What are the concentrations of Cd2+ and Mn²+ in the original solution? concentration: concentration: M Mn2+ MCd+
A KMnO4 (0.02 M) main solution is being given. a.) How many g-(NH4)2SO4 is 1 ml of the main solution.Is FeSO equivalent to 4.6H2O (Mohr salt)? ((NH4)2SO4.FeSO4.6H2O: 392 gmol-1). b.) Find the equivalence point potential in titration of 100 mL of acidic solution of 0.1 N FeSO4 with the main solution (0.02 M KMnO4).
0.9583 g of sample was dissolved in 80 mL of xylene and extracted with three 15 mL quantities of water. The combined aqueous extracts were diluted to 50.0 mL and then shaken with 10 mL toluene. The toluene was then discarded. The absorbance of the aqueous solution when measured in a 1cm path length cell was 0.134 at 278 nm.Calculate the free chlorampenicol content of the sample in ppm, given A(1%, 1cm) = 298 at 278 nm.