8 sin 3+ 5/ is equal to The number lim | sin(x) dx E. 5. 8 sin(x)dx 8 | sin(x) dx 3. 0 8 8. sin(x) dx 3.

Q: X- 2 sin 5x 1. lim x2 x-4 2. lim 70 5x2-3x x'-1 4. lim 114r 3. lim X00 7x + 1 7)

A:

Q: 2 cos(4x) – 4x2 – 2 lim - I→0 sin(2x)- x2 - 2x

A: We have to evaluate the limit limx→0 2 cos(4x) - 4x2 - 2sin(2x) - x2 - 2x

Q: 9. Lim 6x - Sin 2x メ→0 2x +3sin 4X b. lim x²-1 1/2

A:

Q: 3x+7 sin2x x+x.cosx 1- lim- x2-2 lim 2x2+x 3 - lim- x→0 2 - 00+X x→0 sinx.cosx 1 lim x-1- 1-x2 x-3…

A:

Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: lim x → ∞ cos(16/x)^(13.32x^2)

A:

Q: sin(4x) 8. Compute lim x-0 tan(3x)

A: The solution are next step

Q: 3x²+x d (sin-()+sec='(x) (1) Compute lim cot-1(3x+*+1) (ii) Find- X+00 3x2-7 dx tan-1x+tan-1

A: i).…

Q: 1+x V1-x sin-1(x) [3] limx-0

A: To evaluate: lim[x→01+x-1-xsin-1(x)] Solution: lim[x→01+x-1-xsin-1(x)] On simplifying further we…

Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

A:

Q: 1) lim y-4 x+6x+5 2) lim 2-3x-4 t+3t2-12t+4 sin3h-2h 3) lim 4) lim 3-4 gin

A:

Q: lim (cos(9x)) (+) x-0+

A:

Q: i) lim cos x-0 7 πCOS²x x²

A:

Q: 2 sin(-2 x) lim ثم أختر الاجابة ال 0.3) d x-0 4 sin (5 x)

A:

Q: lim h-0 2h sin(x² )dx = -2h cos(1) sin(1)

A:

Q: 1- cos(x/6) lim II

A: Solve the limit

Q: lim sin(x)dx (x² + e²)²

A:

Q: 1 COS X 13. lim- ズ→0 14. lim e -3x+4 15. lim 4x+7 ー-00

A:

Q: 44. lim sin² x x→n/4

A:

Q: 4x[ cos (2x) – 1] sin (5x) – 5x Use L'Hopital's Rule to evaluate lim 4x[ cos (2x) – 1] lim sin (5x)…

A:

Q: (b) lim ln(sin x) x→0+

A: b) limx→0+ln(sin x)

Q: x 0+ (d) lim (1 – 2x)¯4" -4x x→0+ (e) lim (sin æ)-In æ (f) lim (– In æ)*in æ sin x

A:

Q: b) lim sin(x² – 4) х* -16 2х - 3 а) lim %3D V3x² +16 x->2 X->-0

A:

Q: |- lim メ→ X-3 2. lim メ→2 (会 4 メー2 メ*-4 3. lim メ→。 3メ - S;u4X 4. lim メ→。 tau3X 5- lim 1- Cose Sin'e

A: Since you have asked multiple questions. So, we are solving first few for you. If you want any…

Q: 6.The lim x +3 is equal to 1S 3x-4x+n sin t. 7.The [1 is equal to

A: As per guidelines we can answer only one question at a time so if you need more answers kindly…

Q: Vx 6. lim x00 In(x1000) 7. lim 3*-2x X0 x2-x 8. lim 35 sin (nx) cos2 (Tx) 9. lim X-5 2n2(x-5)2

A:

Q: 3. Find lim x sin II

A: Given limx→∞xsin(πx)

Q: 6. Find 1 - cost lim 1+0 t state that it does not exist. e-¹k) o i + tant j + e or

A:

Q: 1-cos (xーT) lim X-n (x-)sin (x-n)

A:

Q: lim * In(sec(2x)) x→0 (sin(3x))³

A: To find the limit.

Q: 2 lim (x + 6) sin(3x) cot (x² + 6x) X→0

A:

Q: sin(4z) f(x) = 9x 0.4 0.35 0.3 0.25 0/5 -0.25 0.25 sin(4x) Evaluate lim 9x Enter at least 3 decimal…

A: Let's find.

Q: (1) lim,-0 √x+9-3 X (2) lim-0 1–c05x x sinx (3) limx-1 x²+3x-4 x-1

A:

Q: 2 sin a-sin 2x limr x-sin x

A: use l hospital rule

Q: 7- sin-(e*) 2 lim V1 - e2x

A:

Q: 18. L6. 4- x² lim lim x² + 3 x→2 3- vx²+5 lim (2x x →2 x →0 21. 19. 20. lim v25 – x2 lim 12 sin (÷)…

A: We have to find out limit

Q: (2-4* limx-1 sin(x³–1) X. x-1

A:

Q: 2x + Vx x² + 4x 3 1. lim 2. lim 7x2 + 2 sin x 3. lim x→-o x + e* 4. lim et 2xe2x In x 6. lim 5. lim…

A: To decide whether the given limit produces an indeterminate form6. limx→∞lnxx

Q: lim -Vx + e* + sin(x)cos(x) 1+ In (x)

A: limx→3-x5+ex1+ln(x)+sin(x)cos(x)=-35+e31+ln(3)+sin(3)cos(3)

Q: 1-cos (4x) e) lim x0 2-2cos (6x) (x+1)2 + (2x+3)³ 3x2(8x+1) h) lim X00

A:

Q: 2 sin x-sin 2x lim х-sin x 3 O -3 6 -6 о O O

A: Given- limx→02sinx-sin2xx-sinx To Find- The valuie of the limit.

Q: 5 sin(6x) lim x→0 3x

A:

Q: V+12-4 3 .lim X-2 tan3x 2. lim X-0 sinax 4). lim X00 x-7x+1 x-2

A:

Q: 1 lim, (e** - 1)sin-+9cos x . x0

A: Given: limx→0ex2-1sin1x+9cosx we know that  limx→0ex2-1=0 and  limx→0sin1x=-1 to 1 so,…

Q: Find the limits

A: Given,                     lim(x,y)→(0,ln2)ex-y     And we have to find its limit.

Q: 2 In(x) c. limx→1 1-ex-I d. limr¬0 sin(x)-x cos(2x)-1

A: We can answer both the question as below.

Q: x2 h) lim - x+0 1- cos?2 x tan 7x i) lim X-0 sin 3x sin(x? + 3x + 2) ji) lim x+ 2

A:

Q: x*cos (x²) 1 – cos 3x lim X-0

A: we have to find the limit of the given expression

Q: 2x e* –1 lim- x→0 sin (2x)

A: Since you have asked multiple questions in a single request, we would be answering only the first…

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.