8 Mecha Using the following combinational logic, determine the output logic. Note! Only the clear bubbles represent an inversion, the black dots are nodes. 1. (A + B)=(AB) AND A NOT A OR (Nor) NONA (O NON) | NOR A MAND B HOT CA 2. 3. NAND A OR A AND A NOT A NOR A NOT A NOT B NOT B NOR A NOT C NAND A P

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### Combinational Logic in Mechatronics

In this exercise, you are required to determine the output logic from the combinational circuits given in the diagrams. Remember, only the clear bubbles represent an inversion, while the black dots indicate nodes.

#### 1. Diagram Analysis
The first diagram involves a combination of AND, OR, and NOT gates:
1. Inputs \(A\) and \(B\) are fed into an **AND gate**.
2. The same inputs \(A\) and \(B\) are fed into an **OR gate**.
3. The outputs from both the AND and OR gates are inputs to a **NOR gate**.
4. Finally, the output of the NOR gate is fed into a **NOT gate** to produce the final output.

Graphical Explanation:
- The top path proceeds from the AND gate (with inputs \(A\) and \(B\)), into a NOR gate.
- The middle path proceeds from the OR gate (with inputs \(A\) and \(B\)), into the same NOR gate.
- The bottom path involves a NOT gate inverting the output of the NOR gate to produce the final output.

#### 2. Diagram Analysis
The second diagram plays with NOT, NAND, and AND gates:
1. The input \(A\) enters a **NOT gate** and the inverted output is fed into an **AND gate**.
2. Simultaneously, the same input \(A\) is passed through a **NAND gate**.
3. The inverse of the second input \(B\) is provided through a **NOT gate** and then to the **NAND gate**.
4. Finally, input \(C\) goes through a series of NOT gates before combining with the NAND gate outputs.

Graphical Explanation:
- The top path features several series of gates, including NOT and NAND, converging into an AND gate with input \(B\). 
- The bottom path passes several inversions before converging into the final NAND gate.

#### 3. Diagram Analysis
The third diagram combines OR, AND, NOR, and NAND gates:
1. Input \(A\) goes through an **OR gate** with input \(B\).
2. Input \(A\) also passes through an **AND gate** with input \(B\).
3. The output of the OR gate and the inverted input \(B\) are inputs to a **NOR gate**.
4.
Transcribed Image Text:### Combinational Logic in Mechatronics In this exercise, you are required to determine the output logic from the combinational circuits given in the diagrams. Remember, only the clear bubbles represent an inversion, while the black dots indicate nodes. #### 1. Diagram Analysis The first diagram involves a combination of AND, OR, and NOT gates: 1. Inputs \(A\) and \(B\) are fed into an **AND gate**. 2. The same inputs \(A\) and \(B\) are fed into an **OR gate**. 3. The outputs from both the AND and OR gates are inputs to a **NOR gate**. 4. Finally, the output of the NOR gate is fed into a **NOT gate** to produce the final output. Graphical Explanation: - The top path proceeds from the AND gate (with inputs \(A\) and \(B\)), into a NOR gate. - The middle path proceeds from the OR gate (with inputs \(A\) and \(B\)), into the same NOR gate. - The bottom path involves a NOT gate inverting the output of the NOR gate to produce the final output. #### 2. Diagram Analysis The second diagram plays with NOT, NAND, and AND gates: 1. The input \(A\) enters a **NOT gate** and the inverted output is fed into an **AND gate**. 2. Simultaneously, the same input \(A\) is passed through a **NAND gate**. 3. The inverse of the second input \(B\) is provided through a **NOT gate** and then to the **NAND gate**. 4. Finally, input \(C\) goes through a series of NOT gates before combining with the NAND gate outputs. Graphical Explanation: - The top path features several series of gates, including NOT and NAND, converging into an AND gate with input \(B\). - The bottom path passes several inversions before converging into the final NAND gate. #### 3. Diagram Analysis The third diagram combines OR, AND, NOR, and NAND gates: 1. Input \(A\) goes through an **OR gate** with input \(B\). 2. Input \(A\) also passes through an **AND gate** with input \(B\). 3. The output of the OR gate and the inverted input \(B\) are inputs to a **NOR gate**. 4.
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