Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:**Graphing Rational Functions Using Transformations**
8) **Task:** Graph the rational function \( R(x) = \frac{2}{(x-3)^2} \) using transformations. Determine the domain, range, asymptotes, and intercepts.
**Explanation and Steps:**
1. **Identify the Basic Function:**
The function given is derived from the basic rational function \( f(x) = \frac{1}{x^2} \).
2. **Transformations:**
- **Horizontal Shift:** The function is horizontally shifted 3 units to the right, resulting in the transformation \( \frac{1}{(x-3)^2} \).
- **Vertical Stretch:** The function is vertically stretched by a factor of 2, giving \( R(x) = \frac{2}{(x-3)^2} \).
3. **Domain:**
- The function is undefined at \( x = 3 \) due to division by zero in the denominator.
- **Domain:** \( x \in (-\infty, 3) \cup (3, \infty) \)
4. **Range:**
- Since \(\frac{2}{(x-3)^2}\) is always positive, the range is all positive values.
- **Range:** \( y \in (0, \infty) \)
5. **Asymptotes:**
- **Vertical Asymptote:** At \( x = 3 \), the function is undefined, making it a vertical asymptote.
- **Horizontal Asymptote:** As \( x \to \pm\infty \), \( R(x) \to 0 \), making \( y = 0 \) a horizontal asymptote.
6. **Intercepts:**
- **X-Intercept:** No x-intercept, as the function does not cross the x-axis.
- **Y-Intercept:** Plugging in \( x = 0 \) provides the y-intercept \( R(0) = \frac{2}{(0-3)^2} = \frac{2}{9} \).
7. **Graph Description:**
- The graph shifts right to \( x = 3 \) and opens upwards.
- It approaches but never touches the x-axis (horizontal asymptote) and has a vertical asymptote at \(
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